REACTION RATE & EQUILIBRIUM,

[dinosaur93]

1.Consider Hydrochloric acid had been added to granulated zinc.

After a couple of minutes or so, bubbles of Hydrogen gas would emerge through the solution (err...I think...)

a.)When the mass of zinc decreases. what happens to the concentration of Hydrogen gas?

b.)When the zinc concentration INCREASES/DECREASES, the volume of the hydrogen gas INCREASES/DECREASES





2. The presence of a catalyst during a reaction increases the rate of reaction without being consumed (or taking place in the reaction).  Why are catalyst usually in the form of powders or fine wire mesh?




3. at 425 degrees, the equilibrium constant K_eq, for this equation is 3 x 10²M^-2. For a particular sample of this reaction mixture at 425 degrees, It was found that the [] of H₂, CO, and CH₃ OH were all .100M.

a.) indicate in which direction the reation must move in order to reach the equilibrium


b.) state 3 possible procedures which would increase the equilibrium yield of methanol in this process.

[thushan]

1.Consider Hydrochloric acid had been added to granulated zinc.

After a couple of minutes or so, bubbles of Hydrogen gas would emerge through the solution (err...I think...) --> that's right

a.)When the mass of zinc decreases. what happens to the concentration of Hydrogen gas?

-> concentration - if the hydrogen exits the solution and you collect it in some kind of gas syringe I would assume the H2 would be the same concentration. if zinc were the limiting reagent, it'd be the volume of H2, not the concentration, that would change.

b.)When the zinc concentration INCREASES/DECREASES, the volume of the hydrogen gas INCREASES/DECREASES
-> concentration? are we talking about [Zn2+] throughout the reaction? If we are...if there is more Zn2+ in the solution, the rxn would have occurred further, therefore V(H2) would be increasing. I get the feeling that's not what you meant though?





2. The presence of a catalyst during a reaction increases the rate of reaction without being consumed (or taking place in the reaction).  Why are catalyst usually in the form of powders or fine wire mesh?

High surface area. Increases collision frequency btwn catalyst and reactants.


3. at 425 degrees, the equilibrium constant K_eq, for this equation is 3 x 10²M^-2. For a particular sample of this reaction mixture at 425 degrees, It was found that the [] of H₂, CO, and CH₃ OH were all .100M.

a.) indicate in which direction the reation must move in order to reach the equilibrium


b.) state 3 possible procedures which would increase the equilibrium yield of methanol in this process.


Sure that's the reaction you meant? :/

[dinosaur93]

1.Consider Hydrochloric acid had been added to granulated zinc.

After a couple of minutes or so, bubbles of Hydrogen gas would emerge through the solution (err...I think...) --> that's right

a.)When the mass of zinc decreases. what happens to the concentration of Hydrogen gas?

-> concentration - if the hydrogen exits the solution and you collect it in some kind of gas syringe I would assume the H2 would be the same concentration. if zinc were the limiting reagent, it'd be the volume of H2, not the concentration, that would change.

b.)When the zinc concentration INCREASES/DECREASES, the volume of the hydrogen gas INCREASES/DECREASES
-> concentration? are we talking about [Zn2+] throughout the reaction? If we are...if there is more Zn2+ in the solution, the rxn would have occurred further, therefore V(H2) would be increasing. I get the feeling that's not what you meant though?

Yeah, I reckon the question was asking about the concentration throughout the reaction.

3. at 425 degrees, the equilibrium constant K_eq, for this equation is 3 x 10²M^-2. For a particular sample of this reaction mixture at 425 degrees, It was found that the [] of H₂, CO, and CH₃ OH were all .100M.

a.) indicate in which direction the reation must move in order to reach the equilibrium


b.) state 3 possible procedures which would increase the equilibrium yield of methanol in this process.


Sure that's the reaction you meant? :/

YEP, the reaction...!

[thushan]

But I see CO on both sides of the equation!