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January 14, 2026, 03:32:12 pm

Author Topic: Suggested answers EXAM 2(Core, geometry / trig, business maths and networks)  (Read 18438 times)  Share 

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georges

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Help how do you do the geometry and trig bearings questions? No idea 3c?

caluuu

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How did you get 4c in Trig?
I keep getting 49m^2






ERGGGGHHHH i did
A= 35 x (14/10)^2
I must have put 25 ins instead of 35!? Poo, hopefully I just can't remember it properly and got 68.6

georges

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Still desperate to figure out where 132 and 222 came from - cant think? Got all right but freaked out with those bearings  :-[

rylee12

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What are the answers for networks questions 1b i and ii)??

i got minimal spanning tree for ii)

if someone could upload a diagram of the tree they got for i) that'll be great!

Aaron

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For question 3c of business maths, were we able to use TVM solver instead of that equation? I wrote down what i saw on tvmsolver, i got the right answer too.

Yes, VCAA accept the values on the Financial solver as 'working out' as long as you listed all the variables
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Conic

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Here:
2012-13: VCE at Parade College (Chemistry, English, Mathematical Methods, Physics and Specialist Mathematics).
2014-16: Bachelor of Science at La Trobe University (Mathematics and Statistics).
2017-17: Bachelor of Science (Honours) at La Trobe University (Mathematics).
2018-21: PhD at La Trobe University (Mathematics).

devonodev

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Thanks for that, heres me hoping they accept the ruled line.

How did people work out 3b in Trig, finding the height of the tree? I don't remember what I got, but working it out now I can't seem to get the right answer.

georges

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Here:

Thanku can't believe I didn't read that it was a rectangle :-( what an idiot!

georges

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Anyone know how to do networks exam 2 part 1iii? Determine shortest distance travelled?

pwntnubs

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Anyone know how to do networks exam 2 part 1iii? Determine shortest distance travelled?

only 2 vertices had an odd degree which means you would have to travel the path connecting those two vertices twice, that path being 70m so just add 70 onto the total distance, 1180+70 = 1250

georges

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Anyone know how to do networks exam 2 part 1iii? Determine shortest distance travelled?

only 2 vertices had an odd degree which means you would have to travel the path connecting those two vertices twice, that path being 70m so just add 70 onto the total distance, 1180+70 = 1250


Still don't get it?

dha1994

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Thanks for the solutions! Does anyone have the answers for the matrices and graphs and relations modules?