How much % of students who get an atar over 90, have already lost their V's ?
Well let us first consider your proposition as a partial differential equation (for reasons which I am sure are obvious)
So, clearly the relation between ATAR (x) and virginity status (y) is quadrilinear and homeotropical, so it follows that
^2-\log_i{\int^4_4{\frac{x}{y}}d\theta = e^{\pi \sqrt{-163}})
which gives the obvious 'trivial' solution of

but also as we convert to spherical coordinates we arrive at the degenerate solution of

This makes it clear that, unless we are operating around the edge of a quasi-ordered commutative ring, we need to modify the model to compensate for
boundless diagonalizable convergence which I'm sure you covered around grade 4 (and I bet you told your teacher you'd never use it!).
So let us find
\sqrt{(dy)^2 -(dx)^2})
which clearly is not degenerate about any of the

eigenvectors of the coefficient matrix.
Substituting our value back into the first equation:

where

So then it follows (and I'm sure you can see where this is going)
that for
}{TREE(x-2\gamma)})
which is a very unstable function that fluctuates violently with changing x.
So it can thus be deduced that while there may appear to be a relationship between x and y, any attempt to convert this clearly ordinal collapsing function into coordinate systems in which there exist 3 spatial coordinates and 1 time coordinate would be a truly fruitless and futile undertaking.

edit: A bit of related light reading for the curious.
http://en.wikipedia.org/wiki/Kruskal%27s_tree_theoremhttp://en.wikipedia.org/wiki/Collapsing_function