ATAR Notes Solutions to Exam 1, 2012

[enwiabe]

Beautifully latexed like in our study guides. Yr 11s be sure to look for our study guide coming out next year!

EDIT:
Small typo error in 10. d. which had a couple of plus signs instead of multipilcation signs. Oops!

Have reuploaded a new version

[enwiabe]

sorry i woke up late, would have had these done earlier otherwise

[b^3]

They look quite nice! ( FTW! )
Except I kinda wish you had of used AlignedAt instead of Aligned

EDIT: 2200^th post.

[enwiabe]

They look quite nice! ( FTW! )
Except I kinda wish you had of used AlignedAt instead of Aligned

These aren't formatted the best because I was going for speed mainly. Notice my MSPaint diagrams

[baddin]

Great solutions, Thank You

[enwiabe]

Great solutions, Thank You

You're welcome

[asdfgh]

Hey guys - just letting you know, that a MUCH quicker way to do question 9d would be to find the angle of the two points relative to the x-axis:

So one point would be 5pi/6 and the other would be pi/4

One is in the 2nd quadrant and the other in the first quadrant.

Hence, 5pi/6 - pi/4

= 10pi/12 - 3pi/12

= 7pi/12

I'm pretty sure this is the method they were expecting people to use, seeing as it was only a 2 mark question.

[rebeckab]

Hey guys - just letting you know, that a MUCH quicker way to do question 9d would be to find the angle of the two points relative to the x-axis:

So one point would be 5pi/6 and the other would be pi/4

One is in the 2nd quadrant and the other in the first quadrant.

Hence, 5pi/6 - pi/4

= 10pi/12 - 3pi/12

= 7pi/12

I'm pretty sure this is the method they were expecting people to use, seeing as it was only a 2 mark question.

This is incredible. And makes so much more sense than all the other solutions I've seen.. If only I had thought of it in the exam

[KevinBacon]

Does anyone know what the marking scheme is going to be for Q2 and the last question?
I didn't include the third solution and might have forgot the "k is and element of Z" part and i didn't simplify the last question.
I wonder how many I'd lose, there was a post about official marking schemes on the methods exam forum.

[thushan]

Hey guys - just letting you know, that a MUCH quicker way to do question 9d would be to find the angle of the two points relative to the x-axis:

So one point would be 5pi/6 and the other would be pi/4

One is in the 2nd quadrant and the other in the first quadrant.

Hence, 5pi/6 - pi/4

= 10pi/12 - 3pi/12

= 7pi/12

I'm pretty sure this is the method they were expecting people to use, seeing as it was only a 2 mark question.

And this is why it's so important to realise that coordinate axes = Argand diagram = Vector field