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November 01, 2025, 09:50:30 am

Author Topic: Faraday's Law  (Read 1453 times)  Share 

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StumbleBum

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Faraday's Law
« on: November 13, 2012, 09:33:19 pm »
0


What does   represent? is it time taken to rotate one quarter turn? or something else...

EDIT:Fixed it.
« Last Edit: November 13, 2012, 09:37:50 pm by StumbleBum »
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BigAl

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Re: Faraday's Law
« Reply #1 on: November 13, 2012, 09:36:12 pm »
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time interval between t1 and t0
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StumbleBum

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Re: Faraday's Law
« Reply #2 on: November 13, 2012, 09:38:11 pm »
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time interval between t1 and t0
Where t1 and t0 represent?
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Phantom-II

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Re: Faraday's Law
« Reply #3 on: November 13, 2012, 09:42:45 pm »
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it is  the time taken for that change of flux to occur. So imagine a sin graph showing the flux: in a quarter of the whole period, the flux has reached its max. from zero, in that case the change in flux is the max flux and change in time is 1/4 of the period

BigAl

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Re: Faraday's Law
« Reply #4 on: November 13, 2012, 09:44:04 pm »
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http://en.wikipedia.org/wiki/Delta_(letter)#Mathematics_and_the_Sciences read this carefully and you will understand
edit: Sorry I didnt get your question at first..Now got you..
« Last Edit: November 13, 2012, 09:45:41 pm by alperenerol »
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datfatcat

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Re: Faraday's Law
« Reply #5 on: November 13, 2012, 09:44:52 pm »
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time interval between t1 and t0

Correct, but to make it clear, it is the final time - initial time within a range, usually a quarter turn, but can be in half a turn (depends on question)
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shivneil.lal

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Re: Faraday's Law
« Reply #6 on: November 13, 2012, 09:45:52 pm »
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t is the duration of the rotation

StumbleBum

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Re: Faraday's Law
« Reply #7 on: November 13, 2012, 09:56:26 pm »
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it is  the time taken for that change of flux to occur. So imagine a sin graph showing the flux: in a quarter of the whole period, the flux has reached its max. from zero, in that case the change in flux is the max flux and change in time is 1/4 of the period

Ahh, had that moment where it clicks! Finally get it thanks.
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StumbleBum

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Re: Faraday's Law
« Reply #8 on: November 13, 2012, 09:57:01 pm »
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t is the duration of the rotation
And this is wrong....
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rife168

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Re: Faraday's Law
« Reply #9 on: November 13, 2012, 10:28:37 pm »
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Also remember
could be:
time taken for a magnet to pass through a coil

distance travelled by a coil/magnet divided by the velocity at which it is travelling. VCAA might do this to try to confuse people a bit. You just have to remember that

and other stuff, it just doesn't always represent time in rotating motors/generators. I just wanted to clear this up.
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