One more urgent question....haha
1) 5.001g of NH4Cl was dissoluted in water to cause it (waters temp) to reduce by 12 degrees
a) find heat energy, mole of the solid and delta H.
Thanks 
4.18=J/(mL*dT) dT being delta T

solve for the J absorbed by substituting the 100mL, and the temperature change to get 5016J, 5.016kJ absorbed.
The mol of NH4Cl is n=m/M=5.001g/53.5gmol=0.09348mol, therefore delta H is 5.016kJ/0.09348mol=53.66kJ/mol, assuming normal equation with compound having a co-efficient of 1 (if it's something else you have to multiply the kJ/mol value by this, it's not literally kj per 1 mole, but kJ per mole of whatever's being described in the equation!!) as it's endothermic delta H is positive so dH=+53.66kJ/mol