It was on the 2009 VCAA exam, I'll link you the question (see pic)
(Image removed from quote.)
a) well you adding hygrogen atoms to the compound so it is a hydrogenation-reaction
b)
PV=nRT
n=PV/(RT) = 105.0*0.510/(8.31*293)=0.0220
c)using the theorem of the conservation of mass we can say that the mass of C10H22 is equivelant to the sum of the mass of the reacted hydrogen and the mass of the mycrene
m(H2)=0.0220*2=0.044
m(C10H22)=m(H2)+m(mycrene)=0.044+1=1.044
d)
Ok, so C10H22 is fully saturated and mycrene is polyunsaturated. So if we find the number of H2 atoms required to turn mycrene into C10H22 we would have the number of C=C double bonds.
The number of moles of C10H22 is equal to the number of moles of mycrene
n(C10H22)=m/M=1.044/142= 0.00735 = n(mycrene)
M(mycrene)=m(mycrene)/n(mycrene)=1/0.00735=136
In comparison M(C10H22)=10*12+22=142
The difference is 6g/mol so 6 Hydrogen atoms have been added, which means 3 H2 molecules reacted, which means there are 3 C=C double bonds in mycrene.