Login

Welcome, Guest. Please login or register.

November 01, 2025, 11:36:36 am

Author Topic: Chemistry 3/4 2013 Thread  (Read 448755 times)  Share 

0 Members and 1 Guest are viewing this topic.

chemdeath

  • Victorian
  • Trailblazer
  • *
  • Posts: 45
  • Respect: 0
  • School: a crap one
Re: Chemistry 3/4 2013 Thread
« Reply #1335 on: September 10, 2013, 05:59:01 pm »
+1
For KNO3, the energy absorbed is more than released, as the delta H is positive and you have to gain energy overall.
We need it in kJ/mol. So (2528.9/1000)kJ/(1.0M*0.05L)=50.58kJ/mol. As it is exothermic delta H is negative, and assuming the reaction is the normal 1:1 mol ratio then delta H=-50.58kJ/mol for HCl+NaOH-->NaCl+H2O

Thanks heaps your a true champ :)

chemdeath

  • Victorian
  • Trailblazer
  • *
  • Posts: 45
  • Respect: 0
  • School: a crap one
Re: Chemistry 3/4 2013 Thread
« Reply #1336 on: September 10, 2013, 06:49:11 pm »
0
One more urgent question....haha
1) 5.001g of NH4Cl was dissoluted in water to cause it (waters temp) to reduce by 12 degrees
a) find heat energy, mole of the solid and delta H.

Thanks :)

clıppy

  • Victorian
  • Forum Leader
  • ****
  • Posts: 707
  • Would you like help?
  • Respect: +68
  • School Grad Year: 2014
Re: Chemistry 3/4 2013 Thread
« Reply #1337 on: September 10, 2013, 07:01:30 pm »
0
One more urgent question....haha
1) 5.001g of NH4Cl was dissoluted in water to cause it (waters temp) to reduce by 12 degrees
a) find heat energy, mole of the solid and delta H.

Thanks :)
I feel like that question is missing something. Was there a calibration factor given? Or a mass/volume of water?
2013 : VCE
2014 : VCE
2015 : UoM


Putting this here so I don't forget about it: http://www.codecogs.com/latex/eqneditor.php

Tutoring in Chemistry. PM if interested.

chemdeath

  • Victorian
  • Trailblazer
  • *
  • Posts: 45
  • Respect: 0
  • School: a crap one
Re: Chemistry 3/4 2013 Thread
« Reply #1338 on: September 10, 2013, 07:13:05 pm »
0
I feel like that question is missing something. Was there a calibration factor given? Or a mass/volume of water?
No CF factor, but the volume of water was 100ml :) Thanks :)

Edward21

  • Victorian
  • Forum Leader
  • ****
  • Posts: 625
  • Don't ask me, all I do is calculate pH.
  • Respect: +27
Re: Chemistry 3/4 2013 Thread
« Reply #1339 on: September 10, 2013, 07:45:03 pm »
+2
One more urgent question....haha
1) 5.001g of NH4Cl was dissoluted in water to cause it (waters temp) to reduce by 12 degrees
a) find heat energy, mole of the solid and delta H.

Thanks :)
4.18=J/(mL*dT) dT being delta T :) solve for the J absorbed by substituting the 100mL, and the temperature change to get 5016J, 5.016kJ absorbed.
The mol of NH4Cl is n=m/M=5.001g/53.5gmol=0.09348mol, therefore delta H is 5.016kJ/0.09348mol=53.66kJ/mol, assuming normal equation with compound having a co-efficient of 1 (if it's something else you have to multiply the kJ/mol value by this, it's not literally kj per 1 mole, but kJ per mole of whatever's being described in the equation!!) as it's endothermic delta H is positive so dH=+53.66kJ/mol
2012 Biology [44] 2013 Chemistry [50] Italian [38] English [48] Health & HD [45] Methods [34] ATAR: 99.10

2014-2016 Bachelor of Biomedicine - The University of Melbourne


Edward21

  • Victorian
  • Forum Leader
  • ****
  • Posts: 625
  • Don't ask me, all I do is calculate pH.
  • Respect: +27
Re: Chemistry 3/4 2013 Thread
« Reply #1340 on: September 11, 2013, 10:32:18 pm »
0
QUESTIONS: what reactions would occur at the anode and cathode with electrolysis of ZnCl2 solution, and KI solution? I think mine are wrong, the internet keeps saying other reactions  ???
« Last Edit: September 11, 2013, 10:34:52 pm by Edward21 »
2012 Biology [44] 2013 Chemistry [50] Italian [38] English [48] Health & HD [45] Methods [34] ATAR: 99.10

2014-2016 Bachelor of Biomedicine - The University of Melbourne


lzxnl

  • Victorian
  • ATAR Notes Legend
  • *******
  • Posts: 3432
  • Respect: +215
Re: Chemistry 3/4 2013 Thread
« Reply #1341 on: September 11, 2013, 10:58:03 pm »
0
QUESTIONS: what reactions would occur at the anode and cathode with electrolysis of ZnCl2 solution, and KI solution? I think mine are wrong, the internet keeps saying other reactions  ???

Strongest reductant present is iodide ion, strongest oxidant is water, so you'll form solid iodine, hydrogen gas and hydroxide ion.
2012
Mathematical Methods (50) Chinese SL (45~52)

2013
English Language (50) Chemistry (50) Specialist Mathematics (49~54.9) Physics (49) UMEP Physics (96%) ATAR 99.95

2014-2016: University of Melbourne, Bachelor of Science, Diploma in Mathematical Sciences (Applied Maths)

2017-2018: Master of Science (Applied Mathematics)

2019-2024: PhD, MIT (Applied Mathematics)

Accepting students for VCE tutoring in Maths Methods, Specialist Maths and Physics! (and university maths/physics too) PM for more details

Edward21

  • Victorian
  • Forum Leader
  • ****
  • Posts: 625
  • Don't ask me, all I do is calculate pH.
  • Respect: +27
Re: Chemistry 3/4 2013 Thread
« Reply #1342 on: September 11, 2013, 10:59:34 pm »
0
Strongest reductant present is iodide ion, strongest oxidant is water, so you'll form solid iodine, hydrogen gas and hydroxide ion.
Thanks! But what about the ZnCl2 solution??
2012 Biology [44] 2013 Chemistry [50] Italian [38] English [48] Health & HD [45] Methods [34] ATAR: 99.10

2014-2016 Bachelor of Biomedicine - The University of Melbourne


lzxnl

  • Victorian
  • ATAR Notes Legend
  • *******
  • Posts: 3432
  • Respect: +215
Re: Chemistry 3/4 2013 Thread
« Reply #1343 on: September 11, 2013, 11:17:03 pm »
+1
You have water in the ZnCl2 solution, so the water will be reduced to form hydrogen gas and hydroxide ions.
The formation of the negative charge at this cathode will be balanced by the salt bridge.
2012
Mathematical Methods (50) Chinese SL (45~52)

2013
English Language (50) Chemistry (50) Specialist Mathematics (49~54.9) Physics (49) UMEP Physics (96%) ATAR 99.95

2014-2016: University of Melbourne, Bachelor of Science, Diploma in Mathematical Sciences (Applied Maths)

2017-2018: Master of Science (Applied Mathematics)

2019-2024: PhD, MIT (Applied Mathematics)

Accepting students for VCE tutoring in Maths Methods, Specialist Maths and Physics! (and university maths/physics too) PM for more details

jgoudie

  • Victorian
  • Trendsetter
  • **
  • Posts: 138
  • Chemisode: an app for studying chemistry
  • Respect: +3
Re: Chemistry 3/4 2013 Thread
« Reply #1344 on: September 12, 2013, 04:06:19 pm »
0
I stand corrected this was in a the 2008 paper, Question 7 i think.

H+ is used when the solution is neutral or acidic, OH- is used when the conditions are alkaline, such as a alkaline battery.  I am pretty sure i have not seen this other than in a multiple choice practice paper.  But if you want to know how to do it normally check below: 

http://www.chemguide.co.uk/inorganic/redox/equations2.html

A very clear to follow set of instructions as always from chemguide.co.uk.
Chemisode: A podcast, iPhone/iPad app for studying VCE chemistry.

Search the appstore: "Chemisode"
http://www.facebook/chemisode34
http://www.facebook/chemisode12
http://jgoudie.podomatic.com/
http://www.youtube.com/mrjasongoudie
Iphone and Ipad apps: 'Chemisode' out in the app store now!

Edward21

  • Victorian
  • Forum Leader
  • ****
  • Posts: 625
  • Don't ask me, all I do is calculate pH.
  • Respect: +27
Re: Chemistry 3/4 2013 Thread
« Reply #1345 on: September 13, 2013, 06:27:23 pm »
0
The (SO4)2- ion can act as an oxidant, thus get reduced in electrolysis, how come this doesn't occur? I was thinking because the cathode is already negative, the ion wouldn't be electrostatically attracted? what do you think?  :D
2012 Biology [44] 2013 Chemistry [50] Italian [38] English [48] Health & HD [45] Methods [34] ATAR: 99.10

2014-2016 Bachelor of Biomedicine - The University of Melbourne


SocialRhubarb

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 313
  • Respect: +34
  • School Grad Year: 2013
Re: Chemistry 3/4 2013 Thread
« Reply #1346 on: September 13, 2013, 11:08:08 pm »
+1
I think the reduction of sulfate only occurs in acidic solutions.

Also, even if the solution is acidic, it's not included on the electrochemical series in the VCAA data book, so we're not expected to use it in equations. The same is true of the nitrate ion.
Fight me.

barydos

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 314
  • Respect: 0
  • School: Nossal High School
  • School Grad Year: 2013
Re: Chemistry 3/4 2013 Thread
« Reply #1347 on: September 14, 2013, 11:32:20 am »
0
In electrolysis, is the forward Z thingo more likely to happen for a pair furthest apart, or closest together?
2012: Methods [47] | Chinese SL [35]
2013: Specialist [48] | Chemistry [41] | Physics [44] | English Language [40]
ATAR: 99.55

BasicAcid

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 207
  • Respect: +135
Re: Chemistry 3/4 2013 Thread
« Reply #1348 on: September 14, 2013, 11:39:41 am »
+1
In electrolysis, is the forward Z thingo more likely to happen for a pair furthest apart, or closest together?

Closer. Strongest oxidant reacts with strongest reductant.

barydos

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 314
  • Respect: 0
  • School: Nossal High School
  • School Grad Year: 2013
Re: Chemistry 3/4 2013 Thread
« Reply #1349 on: September 14, 2013, 11:54:24 am »
0
Closer. Strongest oxidant reacts with strongest reductant.

Thanks! :)

Is electrolysis occurring during recharge or discharge?

And I need help with this question:
« Last Edit: September 14, 2013, 11:58:40 am by Anonymiza »
2012: Methods [47] | Chinese SL [35]
2013: Specialist [48] | Chemistry [41] | Physics [44] | English Language [40]
ATAR: 99.55