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March 24, 2026, 10:01:24 am

Author Topic: Cartesian form  (Read 800 times)  Share 

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samsiexD

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Cartesian form
« on: March 14, 2013, 09:56:33 pm »
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I have to simplify [2(cos(30)+sin(30)]^9 and express it in the form x+yi ( cartesian form)
This is what ive attempted so far

[2(cos(30)+sin(30)]^9
=(2cos(π/6)+2sin(π/6))^9
=(2cis(π/6))^9
=2cis(π/60x9)
=2cis(3π/20)

I stopped there because it didn't look right, can someone help me out please :/

Jaswinder

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Re: Cartesian form
« Reply #1 on: March 14, 2013, 10:05:40 pm »
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is it -512i

Daenerys Targaryen

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Re: Cartesian form
« Reply #2 on: March 14, 2013, 10:08:35 pm »
+3
is there suppose to be an i in the eqn?
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Re: Cartesian form
« Reply #3 on: March 14, 2013, 10:09:56 pm »
+1
I have to simplify [2(cos(30)+sin(30)]^9 and express it in the form x+yi ( cartesian form)
This is what ive attempted so far

[2(cos(30)+sin(30)]^9
=(2cos(π/6)+2sin(π/6))^9
=(2cis(π/6))^9You stuffed up here. It should be

=2cis(π/60x9)
=2cis(3π/20)



I stopped there because it didn't look right, can someone help me out please :/

samsiexD

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Re: Cartesian form
« Reply #4 on: March 14, 2013, 10:16:01 pm »
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Oh i see it now i didnt raise 2 to the power of 9 :P

Jaswinder i got -512i too

Thanks for the help :)