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October 25, 2025, 10:27:02 pm
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Author Topic: BEC'S methods questions  (Read 106792 times)  Share 

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Glockmeister

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Re: BEC'S methods questions
« Reply #600 on: November 06, 2008, 08:51:45 pm »
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Quote from: Quickclaw on November 06, 2008, 04:17:30 pm
Isnt it ? Or am I doing something wrong  :P I'm a bit confused

yeah that would be right, whoops
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bec

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Re: BEC'S methods questions
« Reply #601 on: November 08, 2008, 08:40:04 am »
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I'm back again...



I know it's easy but I'm stuck...
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onlyfknhuman

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Re: BEC'S methods questions
« Reply #602 on: November 08, 2008, 09:54:38 am »
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whats the answer to it btw?
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Quote from: Ken on November 08, 2008, 10:15:53 pm
give me the name list of all the hot chicks u know  ;)

bec

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Re: BEC'S methods questions
« Reply #603 on: November 08, 2008, 09:58:48 am »
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Don't have one...
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onlyfknhuman

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Re: BEC'S methods questions
« Reply #604 on: November 08, 2008, 10:12:18 am »
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sorry im pretty stupid cant help you >:( i tried something but looks wrong
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Quote from: Ken on November 08, 2008, 10:15:53 pm
give me the name list of all the hot chicks u know  ;)

shinny

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Re: BEC'S methods questions
« Reply #605 on: November 08, 2008, 10:36:22 am »
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Quote from: bec on November 08, 2008, 08:40:04 am
I'm back again...



I know it's easy but I'm stuck...

Well it's an upright parabola so when it's less than zero, it'll just be the domain between the two x-ints I think, so it'll be something like:

That was what the question was asking for right? Initially I tried to solve for a to make that relation true, but it's impossible. An upright parabola could never be completely below zero for all x <_<
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bec

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Re: BEC'S methods questions
« Reply #606 on: November 08, 2008, 10:40:17 am »
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oh dw, i just realised i copied it out wrong...
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shinny

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Re: BEC'S methods questions
« Reply #607 on: November 08, 2008, 10:41:26 am »
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That's what I was thinking o_o Strange question when I tried to solve it since there wasn't much I could do, nor did I know what I was meant to
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bec

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Re: BEC'S methods questions
« Reply #608 on: November 08, 2008, 10:43:42 am »
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Yep, note to self -  first step to methods success: LEARN TO READ.
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Mao

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Re: BEC'S methods questions
« Reply #609 on: November 08, 2008, 10:51:20 am »
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Quote from: bec on November 08, 2008, 10:43:42 am
Yep, note to self -  first step to methods success: LEARN TO READ.

VERY.
* Mao lost marks last year because he didn't read very simple instructions....
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bec

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Re: BEC'S methods questions
« Reply #610 on: November 08, 2008, 12:15:42 pm »
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This was from divideby0's thread ages ago - if anyone could explain it, that would be great...

Quote from: DivideBy0 on October 15, 2008, 02:52:55 pm
A game of chance consists of rolling a disc of diameter 2 cm on a horizontal square board. The board is divided into 25 small squares of side 4 cm. A player wins a prize if, when a disc settles, it lies entirely within any one small square. There is a ridge round the outside edge of the board so that the disc always bounces back, cannot fall off and lies entirely within the boundary of the large square:
Prizes are awarded as follows:


When no skill is involved, the centre of the disc may be assumed to be randomly distributed over the accessible region.
a) Calculate the probability in any one throw of winning:
i) 50c
ii) 25c
iii) 12c
iv) 5c
v) no prize
b) The proprietor wishes to make a profit in the long run, but is anxious to charge as little as possible to attract customers. He charges C cents, where C is an integer. Find the lowest value of C that will yield a profit.
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bec

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Re: BEC'S methods questions
« Reply #611 on: November 08, 2008, 02:31:26 pm »
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bump...
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Collin Li

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Re: BEC'S methods questions
« Reply #612 on: November 08, 2008, 03:25:34 pm »
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Basically, within a 4cm by 4cm square, you must ensure the centre of the disc lies within the centre 2cm by 2cm square that is a subset of the 4cm by 4cm square.

Recognise that the diameter physically restricts the area in which the centre of the disc can fall. The squares against the boundary are effectively trimmed by 1 cm because the radius is 1 cm, and the centre of the disc cannot utilise the 1 cm in which the radius of the disc occupies space.

It's a 5x5 board with dimensions 20cm x 20cm. However, due to the 1 cm trim along the boundaries, the total area of the board in which the centre may land: 18cm x 18cm = 324 cm squared. That's your sample space.

It's easier to think of the disc as a "point" and only consider its physical size (a 2 cm diameter disc) for working out things like: "which area can the point lie in, so that the whole disc is in the square" and for the boundaries, where we trim off 1 cm because of the disc occupying space.
« Last Edit: November 08, 2008, 03:36:43 pm by coblin »
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bec

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Re: BEC'S methods questions
« Reply #613 on: November 08, 2008, 04:37:23 pm »
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Oh I know what I was doing wrong! Thanks Coblin - I interpreted the question wrongly... I had the total area as 144cm2.
Got it right now though...
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Collin Li

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Re: BEC'S methods questions
« Reply #614 on: December 17, 2008, 09:13:42 pm »
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This was fun. It was great to hear you did well too. I'm locking this thread and shedding a tear of joy (not really, I don't cry, ahahaha)
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