The amount of a certain chemical in a type A cell is normally distributed with mean of 10 and a standard deviation of 1, while the amount in a type B cell is normally distributed with a mean of 14 and a standard deviation of 2. To determine whether a cell is a type A or a type B, the amount of chemical in the cell is measured and the cell is classified as a type A if the amount is less than a specified value c, and as being of type B otherwise.
a) If c=12 calculate the probability that a type A cell will be misclassified, and the probability that a type B cell will be misclassified.
b) Find the value of c for which the two probabilities of misclassification are equal.
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a) A: normCdf(12,infinity,10,1)=0.0228
B: normCdf(-infin,12,14,2)=0.1587
b) Solve for x: normCdf(x,infin,10,1)= normCdf(-infin,x,14,2)= 11.33= 34/3