I'm having a bit of trouble with titration
We are trying to determine the amount of Nitrogen as ammonium in a fertiliser
We have a sample of fertiliser, weighed it and added de-ionised water to dissolve it. Once it was dissolved, sodium hydroxide was added to it and then it was heated until all the ammonium had turned into vapour. Then we added methyl red indicator and titrated it. I don't understand what titrating the solution actually does in terms of determining the Nitrogen in the fertiliser. If someone could help me that would be awesome
It's a back titration practical, so when we titrate the NaOH with HCl, this is done to find the moles of HCl. And thus work back to find out the moles of NH4(fertiliser).
This is done like this:
n(HCl) = n(NaOH) leftover, since 1:1 ratio
n(NaOH) reacted with fertiliser = n(NaOH) initial - n(NaOH) leftover
thus, n(NaOh) reacted = n(NH4)
When we know the moles of NH4, we can work out the moles of Nitrogen, and then the percentage mass of nitrogen in the fertiliser.
n(N) = n(NH4)
percentage nitrogen in fertiliser = m(N)/m(NH4) x 100
You would probably be asked to compare this with the manufacturer's statement etc.
For example, the manufacturers statement was 27% nitrogen content in the fertiliser, however it was found that such a sum has been overestimated as our results showed a 13% nitrogen content by mass.
And don't forget to include possible errors in the experiment.
