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Author Topic: VCE Chemistry Question Thread  (Read 2878989 times)  Share 

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jyce

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Re: VCE Chemistry Question Thread
« Reply #5250 on: June 20, 2016, 09:02:10 pm »
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oooh that would make much more sense - but isn't there CO2 in the atmosphere as well?

CO2(g) would be more concentrated inside the drink.

blacksanta62

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Re: VCE Chemistry Question Thread
« Reply #5251 on: June 20, 2016, 09:18:24 pm »
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Can anyone explain to me how pH affects enzyme activity from a chemistry pov. My chem teacher said that explanations given in biology would not be sufficient at times. He did explain it to be but it doesn't seem to be sticking/being clear as day. Thank you
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Swagadaktal

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Re: VCE Chemistry Question Thread
« Reply #5252 on: June 20, 2016, 09:27:59 pm »
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Can anyone explain to me how pH affects enzyme activity from a chemistry pov. My chem teacher said that explanations given in biology would not be sufficient at times. He did explain it to be but it doesn't seem to be sticking/being clear as day. Thank you
So enzymes work within an optimum pH range and wane in effectiveness when the pH is increased or decreased. They work on a) dipole-dipole bonds with the substrate and ion-dipole bonds (are there any more? I feel like there's one more) - so by changing the pH it changes the charge of the enzyme, which would change the ion-dipole bonds and dipole-dipole bonds - thus effecting the efficiency of the enzymes coz it cant make those bonds anymore ya feel?

(kind of rusty here we did this chapter ageeeeeeeeees ago) - someone hmu if my wording/theory is wrong
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jyce

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Re: VCE Chemistry Question Thread
« Reply #5253 on: June 20, 2016, 09:53:08 pm »
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So enzymes work within an optimum pH range and wane in effectiveness when the pH is increased or decreased. They work on a) dipole-dipole bonds with the substrate and ion-dipole bonds (are there any more? I feel like there's one more) - so by changing the pH it changes the charge of the enzyme, which would change the ion-dipole bonds and dipole-dipole bonds - thus effecting the efficiency of the enzymes coz it cant make those bonds anymore ya feel?

(kind of rusty here we did this chapter ageeeeeeeeees ago) - someone hmu if my wording/theory is wrong

Changing the pH doesn't change the dipole-dipole bonds; it only changes the ionic interactions.
« Last Edit: June 20, 2016, 09:54:50 pm by jyce »

grannysmith

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Re: VCE Chemistry Question Thread
« Reply #5254 on: June 20, 2016, 09:55:50 pm »
+1
So enzymes work within an optimum pH range and wane in effectiveness when the pH is increased or decreased. They work on a) dipole-dipole bonds with the substrate and ion-dipole bonds (are there any more? I feel like there's one more) - so by changing the pH it changes the charge of the enzyme, which would change the ion-dipole bonds and dipole-dipole bonds - thus effecting the efficiency of the enzymes coz it cant make those bonds anymore ya feel?

(kind of rusty here we did this chapter ageeeeeeeeees ago) - someone hmu if my wording/theory is wrong
Also remember that the enzyme's tertiary structure can be affected (since it can involve ionic interactions), inducing slight but significant conformation changes which ultimately leads to decreased catalytic activity.

zsteve

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Re: VCE Chemistry Question Thread
« Reply #5255 on: June 20, 2016, 10:02:45 pm »
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The reason pH changes the tertiary structure is because of ionic interactions arising (for example) from protonation of -NH2 groups to -NH3+, and deprotonation of -COOH to COO- groups. (In case of low and high pH respectively)
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Swagadaktal

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Re: VCE Chemistry Question Thread
« Reply #5256 on: June 20, 2016, 10:06:03 pm »
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ooh that's a critical distinction, thanks guys
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blacksanta62

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Re: VCE Chemistry Question Thread
« Reply #5257 on: June 21, 2016, 01:06:29 pm »
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Shoot! Those are some very helpful posts. I'm in school rn so I just skimmed over them but it'l make more sense when I read it carefully. Thanks guys  :)
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Jakeybaby

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Re: VCE Chemistry Question Thread
« Reply #5258 on: June 21, 2016, 03:24:47 pm »
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In my latest Chemical Practical Report, the relationship between the concentration of the electrolytes and the voltage produced was discovered, as the concentration increases, so does the voltage. However, a question that is incorporated into the report is in regards to the future predictions that could be made. Would the voltage eventually plateau? What would happen in regards to future events with the galvanic cell with Cu & Mg?
Sorry, does anyone know the answer to this question?
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Re: VCE Chemistry Question Thread
« Reply #5259 on: June 22, 2016, 04:19:44 pm »
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Hello, :)

Could someone please help me answer this question?
What's the difference between rate of reaction and yield of reaction and how can you tell if a changing environment of the reaction system (like increasing temp, decreasing pressure etc) will affect the rate of reaction or the yield of reaction

I really appreciate your help! :)
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Swagadaktal

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Re: VCE Chemistry Question Thread
« Reply #5260 on: June 22, 2016, 08:29:54 pm »
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Hello, :)

Could someone please help me answer this question?
What's the difference between rate of reaction and yield of reaction and how can you tell if a changing environment of the reaction system (like increasing temp, decreasing pressure etc) will affect the rate of reaction or the yield of reaction

I really appreciate your help! :)
Um so for pressure/dilution, if there number of products and reactants are the same (molar amounts), then altering the pressure or concentration of a solution would not have an impact on the yield of reactants and products (it would remain the same), however, increasing pressure and concentration would increase the rate of reaction (collision theory).
For temperature, i think it always changes the yield because all reactions are endothermic or exothermic, but tbh not too sure about that point.
And for rate of reaction only, a catalyst will only increase the rate of reaction and would not alter the yield.

hope this helps
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blacksanta62

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Re: VCE Chemistry Question Thread
« Reply #5261 on: June 22, 2016, 09:16:59 pm »
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Is that all unit 4 stuff? I've heard of some of the things you said (e.g. collision theory) but I just can't recall any of the other stuff  :-\
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Swagadaktal

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Re: VCE Chemistry Question Thread
« Reply #5262 on: June 22, 2016, 09:18:47 pm »
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Is that all unit 4 stuff? I've heard of some of the things you said (e.g. collision theory) but I just can't recall any of the other stuff  :-\
yea all unit 4
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The Usual Student

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Re: VCE Chemistry Question Thread
« Reply #5263 on: June 22, 2016, 09:36:53 pm »
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Um so for pressure/dilution, if there number of products and reactants are the same (molar amounts), then altering the pressure or concentration of a solution would not have an impact on the yield of reactants and products (it would remain the same), however, increasing pressure and concentration would increase the rate of reaction (collision theory).
For temperature, i think it always changes the yield because all reactions are endothermic or exothermic, but tbh not too sure about that point.
And for rate of reaction only, a catalyst will only increase the rate of reaction and would not alter the yield.

hope this helps

just adding on to that,
Diluting can lead to a decrease in the amount of particles capable of reacting, if the substance being diluted is the limiting reagent, then it would lead to a decrease in the yield of the reaction as less particles are present and capable to react/collide. So make sure you check the molar ratios and amounts of the reagents present before you make any decisions and decide what is DRIVING the reaction.

blacksanta62

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Re: VCE Chemistry Question Thread
« Reply #5264 on: June 23, 2016, 07:07:31 am »
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Sorry, does anyone know the answer to this question?
Sorry, haven't covered galvanic cells yet. Hopefully a bump wil result in your question being seen
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