hey !
can someone plz explain this question to me especially where it says " decrease the yield of the reaction"?
thanks!
Hi NimaCr7! Happy to help, but for future questions please explain exactly what it is you don't get about the question. It's important in that it makes it easier for me to help you, and also aids your own learning.
Clearly, decreasing the volume of the reaction vessel will
increase the concentration of all chemical species in the reaction vessel,
both reactants and products. This occurs
regardless of equilibrium effects. Exactly what do I mean by this? Well, decreasing the volume will cause the system to shift LEFT, as there are fewer reactant particles. This causes more NH3 to be produced, and less N2/H2 in the system. HOWEVER, the new equilibrium concentrations of all species (NH3, N2, H2) will
still be higher than the old equilibrium concentrations.
It's important to remember that
Le Chatelier's Principle predicts only a
partial opposition of change.
So we agree that this will increase product concentration. However, because equilibrium shifts to the left, we get a lower
mole amount of product, hence a lower yield of reaction.
There's an important distinction between concentration and mole amounts here, too - here, we get fewer moles. But as we're decreasing the volume, the concentration can increase.
Hence the answer is B.
Hope that helps!
