Can anyone predict what would reaction would take place when KI(aq), KISO3(aq) and H2SO4 are mixed together in deionised water? I'm designing a experiment for school and I'm trying to make an iodine solution for an iodine-starch titration and the teacher told me these ingredients would create the necessary iodine solution, but I'm not sure what reaction would take place? Cheers
EDIT:
I think this might have something to do with triiodide??
I'm not an inorganic chemist but I'll give this a go

Firstly I'm assuming you meant KIO
3(aq) as opposed to KISO
3(aq). (hopefully haha)
So I
- has an oxidation state of -1 and the iodine in IO
3- has an oxidation state of +5. So to generate I
2 (oxidation state 0) in solution I would think that some of I
- would be oxidised at the same time that IO
3- is reduced, while H
2SO
4 is an acid catalyst to help this process occur (much like the acid in acidified dichromate solution for example).
The I
2 probably associates with I
- to generate the triiodide ions you are describing, which (after some googling) I think appears yellow/red normally but when trapped by starch appears blue/black.
I'm not 100% sure all of the above is entirely correct so ask your teacher when you get the chance to!
