Hey guys just wondering if anyone knows how to do this question:
4.150g of tungsten (W) was burned in chlorine (Cl) and 8.950g of tungsten chloride (WCl6) was formed. Find the relative atomic mass of tungsten.
Cheers.
I am making the assumption that information of the molar mass of chlorine was specified (M = 35.50g per mol)
So, initially, we can formulate an equation (excluding states):
W + 3Cl2 --> WCl6
We have 4.150g of W, as well as, ultimately, 8.950g of WCl6, thence, using n = m/M
4.150g/M(W) = 8.950g/(M(W)+M(Cl)*6) (As a 1:1 ratio of tungsten to tungsten chloride exists)
Cross-multiplying, we get:
4.150g * (M(W) + 35.50*6) = 8.950g * (M(W))
therefore, algebraically transposing to solve for M(W):
8.950(M(W)) - 4.150(M(W)) = 35.50*6*4.150
Thus, using a calculator M(W) = 184.156. (which is pretty close to the periodic table value

)