Hey
i have a titration assessed practical coming up soon
the assessment is the we have to find the percentage of household ammonia in a cleaning product by tritrating it against HCl... with the solution diluted to 100mL and an aliquot of 10mL
I've done the calculation part to one...but we are also given density...and i don't quite know where the density fits into it?
the HCl has a concentration of 0.1082
Average volume of HCl titrate used
= 4.85 cm3
No. of moles of HCl reacted = 0.1082 x (4.85 x10-3)
= 5.248 x 10-4 mol
From equation, mole ratio of HCl ≡ NH3 is 1:1,
no. of moles of NH3 reacted = 5.248 x 10-4 mol
No. of moles of NH3 in volumetric flask (diluted) = (100 ÷ 10) × 5.248 x 10-4 mol
= 5.248 x 10-3 mol
No. of mole of NH3 in 10mL (undiluted) = 5.248 x 10-3 mol
Concentration of NH3 = (5.248 x 10-3) ÷ (10 x 10-3) = 5.248 x 10-1 moldm-3
Molar mass of NH3 = 14.01 + 3 (1.0079)
= 17.0337 g mol-1
Therefore, weight-volume percentage of NH3 in window cleaner
= ((17.0337 x 5.248 x 10-1)/ 103) × 100%
= 0.894%
Percentage of ammonia in the window cleaner is: 0.894%
found the percentage of ammonia...but didnt use the density given...could you please tell me where i went wrong?
i'd really appreciate the help
Thankyou
