Uhh, isn't the diploid number 14? The answer says its 7
Note: It doesn't let me attach the screenshot of the question - it says "Your attachment has failed security checks and cannot be uploaded. Please consult the forum administrator." Basically, its question 4c of the 2011 VCAA exam 2
The male has only three chromosomes, but with their homologous pair it is six. So before meiosis, the sister chromatids will form on each chromosome. During meiosis I, the homologues are separated into differing cells. Then again in Meiosis II, the sister chromatids will again separate, hence each gamete of the male will contain 3 chromosomes.
The female has four chromosomes, with homologues it is 8 in total. So again during Meiosis I, the homologues line up and are separated into differing cells, then during meiosis II, the sister chromatids will separate again and so each egg cell has four chromosomes.
Upon fertilisation and formation of the zygote, the sperm, with three chromosomes, fuses with the egg cell, with four chromosomes, thus the zygote will end up with a diploid number of seven chromosomes, but is probably infertile as the chromosomes are not present in homologous pairs.