Equilibrium Constant help

[kaanonball]

I know this is probably a really easy question, just can't seem to find the concentration of D in the below question. (This is question 4., page 226 from the StudyON Chemistry 2 book)

any help?

[monokekie]

I work this question this way:

particle C's concentration decreases by 0.5 mole, its mole ratio with d is 1:2, therefore D should be decreased by 0.5x2 = 1 mole.
So, concentration of C=1.5M, concentration of D=2(initial)-1= 1 M

now let's look at the reactants,
Particle B has the same mole ratio as particle C, therefore it should increase by 0.5M while particle C decreases by 0.5M. Particle A has the mole ratio of 2:1 with particle B, therefore particle A should increase its conc by 0.5x2=1M
So, concentration of A=2+1=3M, concentration of B=2+0.5=2.5M

now use the ratio to work it out, do you get the correct answer? =P

EDIT: 0.07 is it?

[kaanonball]

thanks =]

[kaanonball]

Just need help with another question

[dummy]

(a) V = 3.0 L so
[H2] = 0.31.1 = 0.37 mol L–1
[HI] = 0.33.3 = 1.1 mol L–1
K = use the formula = 49 therefore
 [I2] = 0.067 mol L–1

[dummy]

the solution said 0.5 which would be wrong

[kaanonball]

the solution said 0.5 which would be wrong

oh.. so the solution is wrong?

stupid book, made me think i did it incorrectly...

[dummy]

 ur right  ftw:)

[tripz]

Grr hate wrong solutions...can frustrate you for long amounts of time just trying to find what you did wrong and doing the question 3 times over