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July 19, 2025, 05:48:23 am

Author Topic: UoM Maths Thread  (Read 30976 times)  Share 

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kinslayer

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Re: UoM Maths Thread
« Reply #120 on: June 07, 2014, 03:00:46 am »
+2
hello.
just wondering how i would use the sandwich theorem to figure out the limit of n!/n^n
thanks.

for n > 0,



and:



Can you finish from here?
« Last Edit: June 07, 2014, 03:07:32 am by kinslayer »

Inside Out

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Re: UoM Maths Thread
« Reply #121 on: June 07, 2014, 03:13:33 am »
+1
oh wait yes i get it.. thanks heaps :D

Inside Out

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Re: UoM Maths Thread
« Reply #122 on: June 07, 2014, 03:22:23 am »
0
okay so i get part a.
and then for part b i got the stationary points (0, 20^1/3), (0,0), (20^1/3,20^1/3) and (20^1/3,0). So i was just wondering how would you classify (0, 20^1/3), (0,0) and (20^1/3,0).
cheers.

kinslayer

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Re: UoM Maths Thread
« Reply #123 on: June 07, 2014, 03:31:21 am »
+1
okay so i get part a.
and then for part b i got the stationary points (0, 20^1/3), (0,0), (20^1/3,20^1/3) and (20^1/3,0). So i was just wondering how would you classify (0, 20^1/3), (0,0) and (20^1/3,0).
cheers.

S(x,y) is undefined for x = 0 or y = 0 so you're left with .

Inside Out

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Re: UoM Maths Thread
« Reply #124 on: June 07, 2014, 03:36:35 am »
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S(x,y) is undefined for x = 0 or y = 0 so you're left with .
does that mean all the other 3 points are neither a local maximum, local minimum or saddle point?

kinslayer

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Re: UoM Maths Thread
« Reply #125 on: June 07, 2014, 03:40:09 am »
+1
does that mean all the other 3 points are neither a local maximum, local minimum or saddle point?

The other three points aren't on the curve, so you don't need to classify them. The question is only asking for a point on the curve, nothing else. If you set and  , you will only get one point (x,y) that satisfies both equalities and also makes physical sense.

Inside Out

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Re: UoM Maths Thread
« Reply #126 on: June 08, 2014, 12:25:04 am »
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if fx (derivative of f)=4/(4x-5) what is fxy?

notveryasian

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Re: UoM Maths Thread
« Reply #127 on: June 08, 2014, 12:50:42 am »
+1
if fx (derivative of f)=4/(4x-5) what is fxy?

Is fx the partial derivative of the function f with respect to x? If so, then fxy=0, as all that is treated as a constant when differentiating with respect to y.
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Captain Rascal

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Re: UoM Maths Thread
« Reply #128 on: June 08, 2014, 08:18:57 pm »
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Hello err'body, I am have a royal rumble with the attached mathematical problem and I just can't muster the power to get the right answer. Specifically with the constant in the inhomogeneous boundary condition, which likely relates to an incorrect general solution. But anywho, if one kind soul would be willing to show me a step by step solution to this, I would be most thankful.
A similar problem is sheet 6 Q5 from the problem book (eng maths), which i also got wrong.

Best of luck with exams eeeeeeeeeeeveryone, i believe in you

Phy124

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Re: UoM Maths Thread
« Reply #129 on: June 09, 2014, 02:51:30 am »
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Hello err'body, I am have a royal rumble with the attached mathematical problem and I just can't muster the power to get the right answer. Specifically with the constant in the inhomogeneous boundary condition, which likely relates to an incorrect general solution. But anywho, if one kind soul would be willing to show me a step by step solution to this, I would be most thankful.
A similar problem is sheet 6 Q5 from the problem book (eng maths), which i also got wrong.

Best of luck with exams eeeeeeeeeeeveryone, i believe in you
Would you mind posting up your attempt so I can just point out where you went wrong, instead of writing up an entire solution ;D
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hobbitle

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Re: UoM Maths Thread
« Reply #130 on: June 09, 2014, 07:03:52 am »
+1
What Phy said ^
Those PDE questions can take almost half an hour :-P
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hobbitle

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Re: UoM Maths Thread
« Reply #131 on: June 09, 2014, 07:06:33 am »
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PS where did that problem come from? It looks like from a past exam but most past exams don't make you solve for all three cases of the separation constant. Unless all three result in non-trivial solutions in this instance...
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Hancock

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Re: UoM Maths Thread
« Reply #132 on: June 09, 2014, 09:41:41 am »
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The constant term will arise from the lambda = 0 case.
The cos term in the BC condition will arise from one of the other cases (lambda > 0 or < 0, ceebs figuring it out).

If you have two non-trivial solutions for varying lambda, you apply the principle of superposition. Let's say for instance that the other non-trivial solution for phi comes from the lambda < 0 case. Therefore you can say that:

phi (total) = phi (for lambda = 0) + phi (for lambda < 0)

Just make sure you properly find both functions for each case before superimposing them or it will screw up.
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Captain Rascal

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Re: UoM Maths Thread
« Reply #133 on: June 09, 2014, 12:00:49 pm »
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oh shoot, i figured out where i went wrong. Thanks for the help everybody. I expected it was from the lambda = 0 case but my math had failed me once again. Turns out with the 2 first order boundary conditions for x you get no info on the second integration constant, which i had just set to 0 absentmindedly.

But yea, thanks again and Hobbitle, it's Q10 from the sem 2 2012 paper on the LMS -- it was quite a long exam if i may say so myself, but at least they gave you an odd function for the Fourier series Q. I can just imagine on Wednesday getting into the exam and having to do all 3 cases + a complete Fourier series/integral question oh! the horror

Inside Out

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Re: UoM Maths Thread
« Reply #134 on: June 09, 2014, 10:34:18 pm »
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use partial fractions to integrate: (x+13)/(x^3+2x^2-5x-6)
i can't work out how to factories the bottom polynomial.