Concentration Question

[2NE1]

Does anyone know which one is the 'magic acid' i think the answer should be 0.5 because i think the FSO3SbF5 is the acid

Here is the question:

In 1994, George A Olah, a Hungarian-born American scientist, won the Nobel Prize in Chemistry for his
work on superacids. These are acids that are a billion billion times stronger than 100% sulfuric acid.
These superacids can be used to liquefy coal and to ‘crack’ heavy mineral oils, which could help improve
the processes involved in making petrochemicals. One such superacid is ‘magic acid’ and it is made by
mixing together antimony pentafluoride (SbF5) and fluorosulfonic acid (HSO3F). The reaction is
shown below.
2HSO3F(aq) + SbF5(aq) → FSO3SbF5(aq) + H2SO3F+
(aq)
What concentration, in mol L–1, of magic acid is formed when 2.0 M solutions of each reactant, both with a
volume of 250 mL each, are mixed together? (Assume the reaction goes to completion.)
A. 2 × 10–2
B. 0.25
C. 1.0
D. 2.0

[rhinwarr]

H2SO3F+ should be the acid because it has the hydrogen ions but the answer would still be the same. I got 0.5 as well.

[2NE1]

H2SO3F+ should be the acid because it has the hydrogen ions but the answer would still be the same. I got 0.5 as well.

Theres no possibility that both of the products are the super acid right? because then the concentration would be 1.0 which is one of the options

[alchemy]

Theres no possibility that both of the products are the super acid right? because then the concentration would be 1.0 which is one of the options

Nope, they can't be. Only H2SO3F+ is the magic acid.
Just going to post this here for the sake of completion of this thread:
n(HSO₃F)=2*0.25=0.5mol
n(H₂SO₃F)/n(HSO₃F)=1/2
Hence, n(H₂SO₃F)=1/2*0.5=0.25mol
C(H₂SO₃F+)=n(H₂SO₃F+)/V(H₂SO₃F+)=0.25/0.25=1 mol L^-1
Sorry, I skipped a few lines in my working. Please ask if you don't get any of the above (:

[2NE1]

Nope, they can't be. Only H2SO3F+ is the magic acid.
Just going to post this here for the sake of completion of this thread:
n(HSO₃F)=2*0.25=0.5mol
n(H₂SO₃F)/n(HSO₃F)=1/2
Hence, n(H₂SO₃F)=1/2*0.5=0.25mol
C(H₂SO₃F+)=n(H₂SO₃F+)/V(H₂SO₃F+)=0.25/0.25=1 mol L^-1
Sorry, I skipped a few lines in my working. Please ask if you don't get any of the above (:

same question as before, why for the concentration did you divide by V(H2SO3F+) but not Total Volume which is 500mL

[alchemy]

same question as before, why for the concentration did you divide by V(H2SO3F+) but not Total Volume which is 500mL

Are you referring to the last line of the working out? To find the concentration of a particular reactant, we must divide the number of moles of that reactant by the volume of that reactant. In this case, we calculated H2SO3F+ to have 0.25 moles. There can't be 500ml of magic acid alone as there is another product too! Yes the total volume is 500, but to find the volume of magic acid, we must halve this to get 250ml or 0.25L.

[2NE1]

Are you referring to the last line of the working out? To find the concentration of a particular reactant, we must divide the number of moles of that reactant by the volume of that reactant. In this case, we calculated H2SO3F+ to have 0.25 moles. There can't be 500ml of magic acid alone as there is another product too! Yes the total volume is 500, but to find the volume of magic acid, we must halve this to get 250ml or 0.25L.

But we are trying to find the concentration of the product  H2SO3F+ which is not the same as the H2SO3F, the reactant? How do you know any mLs of the magic acid there are??