Help! Trig

[Edward Elric]

Solve root2sin(2x+pi/4)=cos(2x) for x€[0,2pi]

Any help would be appreciated thanks

[kinslayer]

Solve root2sin(2x+pi/4)=cos(2x) for x€[0,2pi]

Any help would be appreciated thanks

Use the addition formula:



So the equation is:



Can you finish from here?

[Edward Elric]

Ok after what you just did, with the compound angle formula would you
a) get the denominators the same and solve from there or
b) use the double angle formula on the cos2x and sin2x

I tried both methods but still no luck, can you go a bit further please

[kinslayer]

Ok after what you just did, with the compound angle formula would you
a) get the denominators the same and solve from there or
b) use the double angle formula on the cos2x and sin2x

I tried both methods but still no luck, can you go a bit further please

After simplifying, you should get

[Edward Elric]

After simplifying, you should get

Ok thanks i finally got it, I just forgot to put a square bracket multiplying all the terms with the root 2, instead of just the sin(2x). Thanks Very much