chickenfries has questions!

[chickenfries]

Hey guys!!!
i'll just be posting up questions here! So if anyone is up for some physicy fun....

why can't i go
W = Fx = 140cos(23) * 10?

cheers!

[chickenfries]

q2) The optoelectronic device shown in Figure 2 is now reversed in the circuit. What is the magnitude of the
voltage drop across the optoelectronic device in this situation? Provide an explanation for your answer.

in reverse bias there is no current so therefore no voltage across any component?

[speedy]

Hey guys!!!
i'll just be posting up questions here! So if anyone is up for some physicy fun....

why can't i go
W = Fx = 140cos(23) * 10?

cheers!

There's a frictional force. It asks for the work done by the net force. F_net = F_pushing - F_r

Edit: looks like you can use F_net = ma; and the pushing force is a distractor here.

q2) The optoelectronic device shown in Figure 2 is now reversed in the circuit. What is the magnitude of the
voltage drop across the optoelectronic device in this situation? Provide an explanation for your answer.

in reverse bias there is no current so therefore no voltage across any component?

Is it 6V? Since the voltage before is 6V and after is 0V. Therefore V_drop = 6V - 0V = 6V