Methods Exam 1: Discussion!

[Jnf17]

So quick question. I left 2 parts in q9 not in their simplest form. I left part bi as 57/96 rather than 19/32 and bii as 45/57 rather than 15/19. Will this cost me marks? Besides that I found the paper fairly straightforward.

I did the same. Thought I got it wrong but you have just alerted me to the fact that it was just unsimplified!
Cheers.

[GeniDoi]

I did the same. Thought I got it wrong but you have just alerted me to the fact that it was just unsimplified!
Cheers.

They are generally really picky about it so it may cost you marks. Really depends on the
assessors marking your paper (ie luck)

[chuck981996]

So quick question. I left 2 parts in q9 not in their simplest form. I left part bi as 57/96 rather than 19/32 and bii as 45/57 rather than 15/19. Will this cost me marks? Besides that I found the paper fairly straightforward.

I'm sorry, I think this will cost you marks due to the simple fact that not many students will have done it - they generally only award equivalent answers when NOT doing so would fuck up their grade distribution. In this case, I don't even know how you got the answer /96 in the first place - I think most people would have had it in its simplest form straight off.

[Jnf17]

They are generally really picky about it so it may cost you marks. Really depends on the
assessors marking your paper (ie luck)

Yes depends on how the rest of the state go depending on how picky they are. I assume I would lose at least 1 out of 4 minimum for not simplifying. Could quite possibly be 2 out of 4 though. Really just depends.

[DanielJ]

The x or y axis has nothing to do with it. It's just a coincidence that the right endpoint lies on the x axis.

Imagine if the function was restricted to not include the maximum TP that lies at (2,4). Eg, the domain is (-1,1). In this case, I'm sure everyone would still calculate the area between -1 to 1, despite the are not being "bounded". This is the exact same scenario, except we are calculating the area in the local max/min and the (2,3) area.

 There is nothing stopping it, they would have said "and x=3". 27/4 is the only enclosed area.

[Thorium]

[Zigi]

Yo guys, so I asked for another booklet and the supervisor told me that I could do my workings (for the last question) on the following page which was, of course, completely blank
Is this alright or am I stuffed?

[Jcp34]

So it looks like my score is 30-32/40 (can't completely remember my answers). Do you guys think that this will fall into the A range?

[chuck981996]

Yo guys, so I asked for another booklet and the supervisor told me that I could do my workings (for the last question) on the following page which was, of course, completely blank
Is this alright or am I stuffed?

The markers get the whole booklet in it's raw form. It'll be fine

[SeanC]

It was a question I just realised at the end I had stuffed up so in the rush I somehow didn't figure that 3/24 was 1/8. Oh well besides that I only lossed one other mark on the last part of the last question because I used the wrong endpoint.

[T-Infinite]

So it looks like my score is 30-32/40 (can't completely remember my answers). Do you guys think that this will fall into the A range?

If I'm not wrong, according to last year 30-31 would've been a B+ , 32 would be A

[GeniDoi]

There is nothing stopping it, they would have said "and x=3". 27/4 is the only enclosed area.

Would I recieve consequential marks for using incorrect terminals, but having correct integration and area (even though it's incorrect?)

[EasyMoney]

The x or y axis has nothing to do with it. It's just a coincidence that the right endpoint lies on the x axis.

Imagine if the function was restricted to not include the maximum TP that lies at (2,4). Eg, the domain is (-1,1). In this case, I'm sure everyone would still calculate the area between -1 to 1, despite the are not being "bounded". This is the exact same scenario, except we are calculating the area in the local max/min and the (2,3) area.

They wouldn't ask you to do that because it is not valid, nothing is enclosed then

[Rota7]

I wrote my integrals from -1 to 3 and got the answer 8. That said the answer seems to be 27/4 so I am wondering how many marks I would get for my working. I'm thinking either one or two because I identified 4-f(x) and then anti diffed correctly. Despite my terminals and answer being wrong, I am pretty optimistic that I will still get 2 marks.

[Jcp34]

If I'm not wrong, according to last year 30-31 would've been a B+ , 32 would be A
[/quote]

Okay thanks. Hopefully it's an A