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August 26, 2025, 10:37:56 am

Author Topic: Methods Exam 1: Discussion!  (Read 75740 times)  Share 

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speedy

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Re: Methods Exam 1: Discussion!
« Reply #45 on: November 05, 2014, 11:19:29 am »
Yep that's how i did it haha, i just hope +-1/2 (not just +1/2) was an acceptable answer for the second question, cos i don't know if it meant principal square root or just square root (no restrictions?) I drew the hyperbola and pointed to where each gradient would apply.........if i lost that gonna be so pissed haha

The calculator just gives 1/2

Edit: are you saying you don't know if it's +/-root(...)?
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GeniDoi

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Re: Methods Exam 1: Discussion!
« Reply #46 on: November 05, 2014, 11:21:04 am »
 A+ cutoff predictions? Could it go as low as 33-34?
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katiesaliba

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Re: Methods Exam 1: Discussion!
« Reply #47 on: November 05, 2014, 11:21:20 am »
30/40. To get low 30s, is this an okay mark (provided I'm not absolutely massacred in exam 2 tomorrow :O )? 
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BLACKCATT

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Re: Methods Exam 1: Discussion!
« Reply #48 on: November 05, 2014, 11:21:46 am »
I reckon the cutoff for A+ will be around 36

S61778

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Re: Methods Exam 1: Discussion!
« Reply #49 on: November 05, 2014, 11:21:52 am »
For the conditional prob. question with m,

I accidently changed e^-x/5 to e^-x/2 after I wrote the correct integral statement

So, ended up with 2 - (2/sqrt(e))

How many marks would I lose for this?

jumcakes

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Re: Methods Exam 1: Discussion!
« Reply #50 on: November 05, 2014, 11:22:46 am »
Yep that's how i did it haha, i just hope +-1/2 (not just +1/2) was an acceptable answer for the second question, cos i don't know if it meant principal square root or just square root (no restrictions?) I drew the hyperbola and pointed to where each gradient would apply.........if i lost that gonna be so pissed haha

We're given the function as f(x)= root(x^2+3), where the bottom half of the hyperbola is -root(x^2+3) so the function f(x) is only the upper branch :/ but depends on what VCAA has to say.
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DanielJ

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Re: Methods Exam 1: Discussion!
« Reply #51 on: November 05, 2014, 11:23:07 am »
Yep that's how i did it haha, i just hope +-1/2 (not just +1/2) was an acceptable answer for the second question, cos i don't know if it meant principal square root or just square root (no restrictions?) I drew the hyperbola and pointed to where each gradient would apply.........if i lost that gonna be so pissed haha

sqrt (.25) does equal +-1/2, however the gradient of that function at x=1 is increasing, meaning you want the positive one only.
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Aman476

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Re: Methods Exam 1: Discussion!
« Reply #52 on: November 05, 2014, 11:24:08 am »
Yeah true, but i still don't know my spec teacher said if there were no range/domain restrictions you can't assume it means positive or negative (unless its like something that varies with time as it can be in two places at once), yeah so logically i'd say +- but everyone i spoke to wrote +1/2 only......haha can't afford to lose it since i already lost that last point (haha didn't realise f(5/2) was greater than f(6) haha)
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Aman476

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Re: Methods Exam 1: Discussion!
« Reply #53 on: November 05, 2014, 11:26:15 am »
sqrt (.25) does equal +-1/2, however the gradient of that function at x=1 is increasing, meaning you want the positive one only.

Yeah look i think you guys are right, it's annoying though, cos if we had to write a square root function anytime they would expect us to explicitly mark the sign, but they didn't in their question so annoying
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Miokovic

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Re: Methods Exam 1: Discussion!
« Reply #54 on: November 05, 2014, 11:26:53 am »
Here are my preliminary solutions guys :)

I didn't check them, so I may have a few mistakes, but based on conversations with guys who did the exam they seem correct.

P.S. I have a blank copy of the exam too, so I'll upload that next.

your Q10. b. i).
Height isn't v, its v-4?

GeniDoi

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Re: Methods Exam 1: Discussion!
« Reply #55 on: November 05, 2014, 11:29:31 am »
Would you get any marks if you evaluated the integral between -1 and 3? Rather than from -1 to 2? As well as the area being subtracted from 16 of course.
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jumcakes

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Re: Methods Exam 1: Discussion!
« Reply #56 on: November 05, 2014, 11:30:35 am »
your Q10. b. i).
Height isn't v, its v-4?

Triangle OVU (big triangle) was used, not the small shaded triangle. I think there were multiple ways to do this question.
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Carl09

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Re: Methods Exam 1: Discussion!
« Reply #57 on: November 05, 2014, 11:30:50 am »
For the question where we had to sketch the cubic, did we need to label the intercept at (0,0)?  I figured since the question didn't say to then it doesn't matter, but I'm starting to  get worried about it

Miokovic

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Re: Methods Exam 1: Discussion!
« Reply #58 on: November 05, 2014, 11:32:05 am »
Triangle OVU (big triangle) was used, not the small shaded triangle. I think there were multiple ways to do this question.

Ahh I see, thank you

Aman476

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Re: Methods Exam 1: Discussion!
« Reply #59 on: November 05, 2014, 11:40:44 am »
You know i was just thinking, i spoke to a lot of people who were 'leaving exam two from last year till today" i felt so bad for em, because that last question on today's exam 1 was basically just last year's one on exam 2, unlucky!
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