2014 Chemistry Exam Solutions

[Ya Habibi]

Strike that first point - activation energies would've theoretically halved too, but hopefully the second explanation helps you get my drift.

I disagree. I was taught that the unit refers to the coefficient of the subject reactant.

[happy12345]

Would 1-propyl ethanoate be accepted? Because technically couldn't there be a 2-propyl ethanoate formed from propan - 2 - ol. Also, would you consider C13H29COOCH3 a semi structural formula?

[lzxnl]

Would 1-propyl ethanoate be accepted? Because technically couldn't there be a 2-propyl ethanoate formed from propan - 2 - ol. Also, would you consider C13H29COOCH3 a semi structural formula?

I'm not even sure that's possible. You're asking for an alkyl group of C₁₃H₂₉, which implies a C₁₃H₃₀ alkane, but thirteen carbons can only bond to at most 28 hydrogens.

You really should write CH₃(CH₂)₁₂COOCH₃ if you want to be more precise with your semi-structural formula.

I think it's implied with the ester that propyl ethanoate means 1-propyl ethanoate. Someone might want to check that though; VCAA doesn't seem to be picky with it.

[happy12345]

I'm not even sure that's possible. You're asking for an alkyl group of C₁₃H₂₉, which implies a C₁₃H₃₀ alkane, but thirteen carbons can only bond to at most 28 hydrogens.

You really should write CH₃(CH₂)₁₂COOCH₃ if you want to be more precise with your semi-structural formula.

I think it's implied with the ester that propyl ethanoate means 1-propyl ethanoate. Someone might want to check that though; VCAA doesn't seem to be picky with it.

Haha, I meant C13H27COOCH3 - so the right number, just probably not correct because the first half is not in groups??
So if I did 1-propyl ethanoate do you think I'd get that wrong?