Specialist Exam 1 Solutions

[Zealous]

Well, I got bored of studying for my uni exams so I decided to do this years Spesh Exam 1.

Exam 1 Solutions | Please look at your own risk! If you're not feeling confident it might be better off waiting until after results until having a look.

Lemme know if there's anything that needs fixing!

[mtse]

Q8.d) - Isn't the area you found beneath the tan(2x) graph, so for the 1/2arctan(x) graph you should subtract it from the rectangle (root3 x pi/6)?

[Zealous]

Yep! thanks for spotting that, I'll fix it.

[Deshouka]

Yep! thanks for spotting that, I'll fix it.

But isn't it the area of the inverse bounded by the y-axis which is equal to the area you're trying to find?

[GeniDoi]

Q2 b) a should = 1.5m/s^2 as direction is specified to be downward in the question. -1.5m/s^2 downward = 1.5m/s^2 upwards.

[Zealous]

But isn't it the area of the inverse bounded by the y-axis which is equal to the area you're trying to find?

The area we found under tan(2x) was bound by the x-axis, so we need to take the otherside of the "rectangle".

Q2 b) a should = 1.5m/s^2 as direction is specified to be downward in the question. -1.5m/s^2 downward = 1.5m/s^2 upwards.

Hahaha just noticed that and fixed it 30 seconds before you posted.

[HighTide]

The area we found under tan(2x) was bound by the x-axis, so we need to take the otherside of the "rectangle".

Hahaha just noticed that and fixed it 30 seconds before you posted.

Would we lose marks for writing (24+20g) Newtons?

[boingo]

Q2 b) a should = 1.5m/s^2 as direction is specified to be downward in the question. -1.5m/s^2 downward = 1.5m/s^2 upwards.

do you think they'd accept leaving it as 3/2 m/s^2? I'd think exact values should be fine but not sure haha

[GeniDoi]

do you think they'd accept leaving it as 3/2 m/s^2? I'd think exact values should be fine but not sure haha

Yeah of course. This isn't physics

[byCrypt]

Would we lose marks for writing (24+20g) Newtons?

I did that too. I hope not tho. They didn't specify a certain form.

[boingo]

Yeah of course. This isn't physics

Phew. Cheers man. Already lost 5 marks so can't afford to lose anymore. Anyway, good luck on Monday

[Escobar]

for 4b, is 0 acceptable instead of 0+0i?

[Splash-Tackle-Flail]

I would say so, but then again I'm no assessor. But I have never been told I can just write 0. ^

[Splash-Tackle-Flail]

for 4b, is 0 acceptable instead of 0+0i?

Here's some more comforting proof

"To describe the complex numbers, we use a formal symbol i representing √−1; then a complex number is an expression of the form
(2) a + bi, a, b real numbers.
If a = 0 or b = 0, they are omitted (unless both are 0); thus we write
a + 0i = a, 0 + bi = bi, 0 + 0i = 0 ."

from http://math.mit.edu/~jorloff/suppnotes/suppnotes03/c.pdf

[de]

For the tan graph question, my gradient was considerably less steep at the origin , is that a problem?