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September 10, 2025, 07:56:19 am

Author Topic: Mathematics Question Thread  (Read 1626434 times)  Share 

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Mate2425

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Re: Mathematics Question Thread
« Reply #3120 on: October 28, 2017, 09:03:16 pm »
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Thank you very much!!!  :)

Aaron12038488

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Re: Mathematics Question Thread
« Reply #3121 on: October 29, 2017, 02:25:24 pm »
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help!
Bill thinks he can afford a
mortgage payment of $800
each month. How much can he
borrow
, to the nearest $100, over
25 years at 11.5% p.a.?   

itssona

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Re: Mathematics Question Thread
« Reply #3122 on: October 29, 2017, 08:05:43 pm »
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heey, suppose I have the equations
cosx=1/root 2 and sinx=-1/root 2

and my domain is x is between 0 and pi/2

what answer fits both equations??

would I just say that sinx has no solutions in our domain?
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jamonwindeyer

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Re: Mathematics Question Thread
« Reply #3123 on: October 29, 2017, 08:11:50 pm »
+1
help!
Bill thinks he can afford a
mortgage payment of $800
each month. How much can he
borrow
, to the nearest $100, over
25 years at 11.5% p.a.?   

Hey! Form a series of the amount owed after each month, with \(P\) being the principal. Note that \(1+r=1+\frac{0.115}{12}\approx1.0096\). Your first few terms would be:



This would look the same as usual for this sort of question. Generalising:



Then just set \(n=25\times12=300\), and evaluate! ;D

jamonwindeyer

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Re: Mathematics Question Thread
« Reply #3124 on: October 29, 2017, 08:13:56 pm »
+2
heey, suppose I have the equations
cosx=1/root 2 and sinx=-1/root 2

and my domain is x is between 0 and pi/2

what answer fits both equations??

would I just say that sinx has no solutions in our domain?

You are looking for the quadrant where sine is negative and cosine is positive, that's the fourth quadrant! We can see the related angle is 45 degrees using the exact ratio triangles on our reference sheet, so that means the common solution is \(x=360-45=315\) degrees, using the angles of any magnitude 'system' (angles in the fourth quadrant are expressed as \(360-\theta\) ;D

RuiAce

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Re: Mathematics Question Thread
« Reply #3125 on: October 29, 2017, 10:13:05 pm »
+2
You are looking for the quadrant where sine is negative and cosine is positive, that's the fourth quadrant! We can see the related angle is 45 degrees using the exact ratio triangles on our reference sheet, so that means the common solution is \(x=360-45=315\) degrees, using the angles of any magnitude 'system' (angles in the fourth quadrant are expressed as \(360-\theta\) ;D
Although it specified that x was between 0 and pi/2 instead of 0 and 2pi. So therefore there'd be no solutions?

(Of course, there's always the possibility that pi/2 was a typo.)

jamonwindeyer

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Re: Mathematics Question Thread
« Reply #3126 on: October 29, 2017, 10:44:08 pm »
+2
Although it specified that x was between 0 and pi/2 instead of 0 and 2pi. So therefore there'd be no solutions?

(Of course, there's always the possibility that pi/2 was a typo.)

Oh I totally read it as \(2\pi\), so yeah, whichever sssona ;D

itssona

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Re: Mathematics Question Thread
« Reply #3127 on: October 31, 2017, 05:38:40 pm »
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Thanks Jamon and Rui :)

alsoo so if I was summing a geometric sequence - how many terms of -16+8-4+... must be taken to give a sum of -43/4

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Opengangs

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Re: Mathematics Question Thread
« Reply #3128 on: October 31, 2017, 05:44:26 pm »
+1
Thanks Jamon and Rui :)

alsoo so if I was summing a geometric sequence - how many terms of -16+8-4+... must be taken to give a sum of -43/4


Use the sum to n terms of a GP, and equate it to -43/4. Your goal now is to find the value of n.

itssona

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Re: Mathematics Question Thread
« Reply #3129 on: October 31, 2017, 05:52:42 pm »
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Use the sum to n terms of a GP, and equate it to -43/4. Your goal now is to find the value of n.
oh thanks!!
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taliakaragiannis8

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Re: Mathematics Question Thread
« Reply #3130 on: October 31, 2017, 06:50:43 pm »
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Hi there, could  I have some help with this. Find the x-intercept of the tangent to the curve y = (4x - 3)/(2x+1) at the point where
x=1.

RuiAce

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Re: Mathematics Question Thread
« Reply #3131 on: October 31, 2017, 06:57:38 pm »
+1
Hi there, could  I have some help with this. Find the x-intercept of the tangent to the curve y = (4x - 3)/(2x+1) at the point where
x=1.


itssona

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Re: Mathematics Question Thread
« Reply #3132 on: November 05, 2017, 02:44:18 pm »
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for limiting sum, is it always a/1-r
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jamonwindeyer

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Re: Mathematics Question Thread
« Reply #3133 on: November 05, 2017, 04:36:18 pm »
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for limiting sum, is it always a/1-r

Yep! Provided the limiting sum actually exists, that is the formula you use to calculate it ;D

itssona

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Re: Mathematics Question Thread
« Reply #3134 on: November 05, 2017, 04:47:12 pm »
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Yep! Provided the limiting sum actually exists, that is the formula you use to calculate it ;D
ooh awesomeee! :)
HSC 2018 : Maths 3U, Maths 4U, English Advanced, Biology, Physics, Chemistry