how do you do this
Hey! So for the first bit, the total cost is given by the the cost per hour, multiplied by the number of hours spent travelling:
\times h)
Now \(h\) can be found, because we know it is travelling 1500km at a speed of \(s\) kilometres per hour (we assume the units match, at least). So:

So we sub that in above:
=1500\left(s+\frac{9000}{s}\right))
The rest of the question is your usual process:
- Differentiate the function
- Find where that derivative is equal to zero to find a maxima/minima for speed
- Prove it is a minimum using second derivative check (or otherwise)
- Sub this speed back into the cost function to get a value
This is something you should have been doing a lot of in this topic, but if you've had trouble with it feel free to post some working and we can try and guide you!
