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May 31, 2025, 11:20:47 am

Author Topic: 3U Maths Question Thread  (Read 1431565 times)  Share 

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RuiAce

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Re: 3U Maths Question Thread
« Reply #3555 on: July 26, 2018, 08:55:55 pm »
+4
Hi, how do I solve q24 and 25 for permutations? Thank you in advance :))
I found the answer to Q25. Will get back to Q24 if nobody beats me to it

RuiAce

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Re: 3U Maths Question Thread
« Reply #3556 on: July 27, 2018, 06:18:59 pm »
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Hi, how do I solve q24 and 25 for permutations? Thank you in advance :))
Essentially the alternating roles forces two splits to occur in the analogy.


key to success

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Re: 3U Maths Question Thread
« Reply #3557 on: July 28, 2018, 08:07:48 pm »
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Could someone help plz. Thanks!
HSC 2018
Physics, Chemistry, Economics, Extension 1 Mathematics, Advanced English, Studies of religion (2017), Advanced Mathematics (2017)

RuiAce

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Re: 3U Maths Question Thread
« Reply #3558 on: July 28, 2018, 08:17:36 pm »
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Could someone help plz. Thanks!
Which part are you having trouble with?

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Re: 3U Maths Question Thread
« Reply #3559 on: July 28, 2018, 09:58:56 pm »
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Which part are you having trouble with?

aii- how do we sketch the function and also bi, please.
Thank you very much :)))
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Physics, Chemistry, Economics, Extension 1 Mathematics, Advanced English, Studies of religion (2017), Advanced Mathematics (2017)

RuiAce

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Re: 3U Maths Question Thread
« Reply #3560 on: July 28, 2018, 10:07:53 pm »
+2



Which of course, you should know how to sketch because it's just a horizontal line. Just remember that it's only defined on \( 0\leq x \leq 1\), so you have endpoints.

The answer to b) i) is just \( \binom{7}{k} 2^{7-k}3^k \) using your reference sheet.

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Re: 3U Maths Question Thread
« Reply #3561 on: July 28, 2018, 11:03:59 pm »
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Which of course, you should know how to sketch because it's just a horizontal line. Just remember that it's only defined on \( 0\leq x \leq 1\), so you have endpoints.

The answer to b) i) is just \( \binom{7}{k} 2^{7-k}3^k \) using your reference sheet.

Thank you so much- that helps heaps!
HSC 2018
Physics, Chemistry, Economics, Extension 1 Mathematics, Advanced English, Studies of religion (2017), Advanced Mathematics (2017)

Mate2425

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Re: 3U Maths Question Thread
« Reply #3562 on: August 03, 2018, 02:19:16 pm »
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Hi does anyone know how to derive the differnt parametric forms of the parabola in case you forget them in a test?

Thank you.

envisagator

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Re: 3U Maths Question Thread
« Reply #3563 on: August 03, 2018, 02:57:28 pm »
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Hi does anyone know how to derive the differnt parametric forms of the parabola in case you forget them in a test?

Thank you.
Parametric forms of the parabola are given in the formula sheet.
2018 HSC: English Standard          Mathematics EXT 1,2          Physics          Engineering Studies

RuiAce

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Re: 3U Maths Question Thread
« Reply #3564 on: August 03, 2018, 04:21:52 pm »
+2
Hi does anyone know how to derive the differnt parametric forms of the parabola in case you forget them in a test?

Thank you.
Parametric forms of the parabola are given in the formula sheet.
Yeah this for the most part.

For anything that's not on the reference sheet (e.g. point of intersection of the tangents) you will need to derive it, unless it's explicitly given in front of you in the exam.)

Mate2425

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Re: 3U Maths Question Thread
« Reply #3565 on: August 04, 2018, 02:43:00 pm »
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Hi everyone need help with Q7 MC for HSC Paper 2016. How do you go about when you have two parts in the same question?
http://educationstandards.nsw.edu.au/wps/wcm/connect/756b83c4-d51a-4033-ae36-ff7cd39d4369/2016-hsc-maths-ext-1.pdf?MOD=AJPERES&CACHEID=ROOTWORKSPACE-756b83c4-d51a-4033-ae36-ff7cd39d4369-lCkVKC5

Thank you!

RuiAce

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Re: 3U Maths Question Thread
« Reply #3566 on: August 04, 2018, 02:55:28 pm »
+3

beeangkah

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Re: 3U Maths Question Thread
« Reply #3567 on: August 04, 2018, 02:59:23 pm »
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Hey I just tried this question and did the differential twice to get acceleration, then equated it to 0 and solved for t.
I got a negative value for t, but when I subbed it back into the velocity equation it worked out? I got 52 for the answer.

RuiAce

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Re: 3U Maths Question Thread
« Reply #3568 on: August 04, 2018, 03:05:49 pm »
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Hey I just tried this question and did the differential twice to get acceleration, then equated it to 0 and solved for t.
I got a negative value for t, but when I subbed it back into the velocity equation it worked out? I got 52 for the answer.
If you set \( -104 \sin (4t+\alpha) = 0\), which isn't really best done with an ASTC approach, you should be using boundary angles and realising that \( 4t+\alpha =..., 0, \pi, 2\pi, 3\pi, 4\pi,...\) and so on. As you say, if you take the solution \( 4t+\alpha = 0\), you get something negative for \(t\). So you only consider the ones starting from \(\pi\).

That will keep the value of \(t\) positive.

Mate2425

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Re: 3U Maths Question Thread
« Reply #3569 on: August 04, 2018, 03:15:50 pm »
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Thank you so much Rui, i now understand clearly. On a side note could you also please explain what the phase does in the normal displacement of a particle formula because i am struggling to understand where/ why we use it.
Thannnkkkks!  :)