Hey, Can someone please explain to me how to do part D.
Ksp= 1.41 x 10^-12
Thanks!
Hey there,
There are a few steps involved, but hopefully I'm making some sense!
1. Write an equation (as always)
Note the molar ratios - the OH has 2.
2. Write a K
sp expression:
That's the solubility product, considering the OH's molar ratio. We don't divide by the magnesium hydroxide as that's a solid when it isn't dissolved.
3. Replace the concentration of Mg
2+ with x. We know this to be the same concentration as that of magnesium hydroxide (what we're trying to figure out).
4. Solving for x gives: 7.06 *10
-5M. This is the molar solubility of Mg(OH)
2 - the amount of moles that can be dissolved in a litre of water.
An aside: regular solubility is measured in g/L. To convert, just multiply 7.06 *10
-5 by the molar mass of Mg(OH)
2