cartesian eqn help

[Jordan23]

r(t)=(e^t+e^(-t))i + (e^t-e^(-t))j

12B q11 c from Essentials

[TrueTears]

let and

x = 2cosh(t) and y = 2sinh(t)

[Jordan23]

?? We don't do sinh and cosh functions do we and it is still in terms of t

[TrueTears]

nah it's not in the spesh course but I just remember it coz it helps.

My final line is not in terms of t.

[Jordan23]

sorry lol i just don't understand the last line. Thought it was like syntax or something. Is this the only way to do the question why would it be in the spesh book?

[TrueTears]

Nah there's another way kamil did it in another thread, I just forgot.

EDIT: can anyone else see LaTeX? It's not showing up for me =S

[TonyHem]

Nah there's another way kamil did it in another thread, I just forgot.

EDIT: can anyone else see LaTeX? It's not showing up for me =S

not showing up for me either.

[NE2000]

Can't see LaTeX :S

[TrueTears]

Damn. That sucks.

[kamil9876]

Nah there's another way kamil did it in another thread, I just forgot.

EDIT: can anyone else see LaTeX? It's not showing up for me =S

http://vcenotes.com/forum/index.php/topic,15142.msg162335.html#msg162335

[QuantumJG]

r(t)=(e^t+e^(-t))i + (e^t-e^(-t))j

12B q11 c from Essentials

sinh (shine) and cosh (cosh) are called hyperbolic functions (since sinh^2(x) - cosh^2(x) = 1 - equation of a hyperbola), these are just as easy to remember as sin^2(x) + cos^2(x) = 1.

But basically with these parametric equations i is the basis for the x-axis and j is the basis of the y-axis.

You could try another method to solve for these parametric equations but they are the hyperbolic trig functions.