Suggested Answers (and Discussion) of the Further Maths Exam!

[blossum]

Looks like I fucked further 7 wrong on the first bloody exam 

Hey there, anything over 80% is extremely honouring. Maybe you have high expectations but this is still a promising score, and I hope it strives you to do your best in exam 2. Both exams are weighted equally, so I believe you can pull it up in the next one c:
This only is of help to some people, but, my cohort's average for the mock exam we had was under 40%, so there is promise of many people being below you and you having a decent study score x]

[twinsniper]

Graphs and relations (module 4)
Can someone please explain to me how they did the last question? ... I had no idea how to do it and just ended up guessing

First, at T=10, you use the third equation as per the constraints, the thir equationn being k*t
You know that the journey was a total of 800m, and that it took her 10 minutes to reach the shop, or to cover the 800m. The fact that she went at a different pace or stopped for a while is irrelevant, as the Hybrid funtion gives the distance from her house at any particular point, and regardless the distance from her house at T=10 is 800m.
To work out the average rate of travel, divide the distance by time, or 800/10=80, which gives you your K value. Next, you know that at T=a, the distance is 600m, as per the second equation in the Hybrid funtion. Thus, k*t bceomes k*a=600, a=600/k, k=80, then a=600/80=7.5

[busssar]

First, at T=10, you use the third equation as per the constraints, the thir equationn being k*t
You know that the journey was a total of 800m, and that it took her 10 minutes to reach the shop, or to cover the 800m. The fact that she went at a different pace or stopped for a while is irrelevant, as the Hybrid funtion gives the distance from her house at any particular point, and regardless the distance from her house at T=10 is 800m.
To work out the average rate of travel, divide the distance by time, or 800/10=80, which gives you your K value. Next, you know that at T=a, the distance is 600m, as per the second equation in the Hybrid funtion. Thus, k*t bceomes k*a=600, a=600/k, k=80, then a=600/80=7.5

Thank you!!!

[Izabella kendall]

Geometry
4. A (not 100%, what's your answer?)

I got c for this question

[Manige123]

Can I please get an answer for question 4 geometry!!
I got E. 6.35am but im seeing conflicting results! Someone who could confirm this answer would be appreciated

[plato]

can someone explain to me how to work out Q8 on the Graphs and Relations module??? thanks

Twinsniper offered an appropriate explanation for Q8 in Graphs while I was composing this one - but here is my explanation anyway.

The equation for the final section of the graph is distance = kt. This is the same as y=mx+c where c=0.
Since y=mx+0 goes through the origin, so must distance = kt

Since the line distance = kt joins (0, 0) and (10, 800), the gradient of this line is 80
That means k=80 and the equation of the line, between t=a and t=10, is given by distance = 80t

Now find the value of t where this line distance = 80t crosses the line distance = 600
That is, solve  80t = 600.
This gives the value of t=a=7.5.

[apan]

Haha wow congrats I hope your next exam is as successful.
Did you figure out how to do those questions?

I did matrices and networks!
Unsure:
Core Q2 (picked B, OP says maybe D)
Core Q24 (picked C, OP says maybe E)
Matrices Q8 (picked A, OP says maybe E)

Wrong:
Core Q8 (picked B) - I ruled out the right answer (C) first because I didn't even think about it haha
Core Q11 (picked C)- I totally forgot to log(y) on my CAS and calculated the regression without it
Matrices Q6 (picked C) - silly mistake, flew straight over the zero

Definitely think you got 37 :-)
Core Q2 I answered D but I 100% understand why it's C makes sense, under 50 and over 50 does have some sort of natural order! You wouldn't order it as: over 50, under 50 imo.
Core Q24 I chose C! I also checked with my teacher and she agreed it was C! People mixed their negative and positives up! But pretty sure annuities are treated as investments...?
Matrices Q8 was 100% A! It was a normal dominance matrix so I don't understand why some people were adding columns? You always add rows

The ones I got wrong were:
Q7 - picked D because I didn't read the 'at least 2' properly 😂 forgot to add the 1!
And 2 questions from graphs and relations!

So unless some magic happens and vcaa accepts 2 answers for Q2 (here's hoping!) Sitting on an average score :/
Thankfully I understand them now Hopefully we can smash Exam 2!

[EdwinJS]

Can I please get an answer for question 4 geometry!!
I got E. 6.35am but im seeing conflicting results! Someone who could confirm this answer would be appreciated

I don't do the geometry module but I got 6:35 when I did it. 8° Difference of both locations, and you are told that 15° equates to one hour.
8/15 = 0.53333... 0.53 of 60 minutes is 31.98minutes. 31.98minutes or 32minutes added on to 6:03am is 6:35am. However because its the longitude that equates to one hour someone may be needing to correct me. Btw I don't do the Geometry module 

[Manige123]

have we established what the answer is to Question 2 core? B OR D??

[EdwinJS]

Twinsniper offered an appropriate explanation for Q8 in Graphs while I was composing this one - but here is my explanation anyway.

The equation for the final section of the graph is distance = kt. This is the same as y=mx+c where c=0.
Since y=mx+0 goes through the origin, so must distance = kt

Since the line distance = kt joins (0, 0) and (10, 800), the gradient of this line is 80
That means k=80 and the equation of the line, between t=a and t=10, is given by distance = 80t

Now find the value of t where this line distance = 80t crosses the line distance = 600
That is, solve  80t = 600.
This gives the value of t=a=7.5.

But this is not accounting for her remaining stationary for x minutes? I don't think you can use the average travel rate to find a... This question is flawed

[blossum]

Definitely think you got 37 :-)
Core Q2 I answered D but I 100% understand why it's C makes sense, under 50 and over 50 does have some sort of natural order! You wouldn't order it as: over 50, under 50 imo.
Core Q24 I chose C! I also checked with my teacher and she agreed it was C! People mixed their negative and positives up! But pretty sure annuities are treated as investments...?
Matrices Q8 was 100% A! It was a normal dominance matrix so I don't understand why some people were adding columns? You always add rows

The ones I got wrong were:
Q7 - picked D because I didn't read the 'at least 2' properly 😂 forgot to add the 1!
And 2 questions from graphs and relations!

So unless some magic happens and vcaa accepts 2 answers for Q2 (here's hoping!) Sitting on an average score :/
Thankfully I understand them now Hopefully we can smash Exam 2!

My friend did that with Q7 too x]
My cohort's pretty weak so I don't feel too happy haha. But then again, I haven't done.. optimal studying this year.. or this month,, or week,, B^0
Thanks for boosting my morale! I'm gonna ask how you do afterwards, okay? c:

[DontDrinkAndDerive]

Twinsniper offered an appropriate explanation for Q8 in Graphs while I was composing this one - but here is my explanation anyway.

The equation for the final section of the graph is distance = kt. This is the same as y=mx+c where c=0.
Since y=mx+0 goes through the origin, so must distance = kt

Since the line distance = kt joins (0, 0) and (10, 800), the gradient of this line is 80
That means k=80 and the equation of the line, between t=a and t=10, is given by distance = 80t

Now find the value of t where this line distance = 80t crosses the line distance = 600
That is, solve  80t = 600.
This gives the value of t=a=7.5.

This makes sense - I stand corrected!

It seems the key point (which I missed initially) is that the line segment has (or would have) a y-intercept of 0. So you can get the value of k using rise over run from (0,0) to (10, 800).

Once k is known then we've got enough info to work with. Thanks!

[benwilko]

does anyone have a method for Q4 geometry. I chose A but am thinking it's E?
Thanks

[SexGodDosia]

Q.4 Geometry pre confident its E, Sun rises from the furthest east point(180e) until closing in on equator (0)

So sun hits M(150deg) at 6:03 and then will travel 8deg to 142e(8x4), Arriving at 6:35am (due to there being 1 Tz)

For a simpler example, Melbourne is at 144 E and perth is at 116E. If melbourne and perth were on one 1tz and sun would rise at 6am in melbourne it wouldn't rise in perth until (28x4) 1hr 52mins later (7:52)


Also food for thought i did e for q.24, and am unsure. St michaels maths teacher did live stream with the age and got E as well so idk (http://www.theage.com.au/victoria/the-80000-question-that-divided-vce-further-maths-students-20161028-gsdd7o.html) Scroll half way down.

[Syedali_]

Q2 core ,
I have a gut feeling its D , if some has a reason its not please explain
Thanks