Login

Welcome, Guest. Please login or register.

October 10, 2025, 09:18:23 am

Author Topic: Physics: Discussion, Questions & Potential Solutions  (Read 54311 times)

0 Members and 2 Guests are viewing this topic.

izam25

  • Adventurer
  • *
  • Posts: 16
  • Respect: 0
Re: Physics: Discussion, Questions & Potential Solutions
« Reply #30 on: November 14, 2018, 03:22:56 pm »
0
This q will vary between students due to gradient calculation.
i god 6.x10^26. dont remember the decimal

Alright cool, got something similar but thought it was way off hahahah

jpulvirenti

  • Adventurer
  • *
  • Posts: 21
  • Respect: 0
Re: Physics: Discussion, Questions & Potential Solutions
« Reply #31 on: November 14, 2018, 03:26:54 pm »
0
Alright cool, got something similar but thought it was way off hahahah

How did u do the speaker question

lolno

  • Fresh Poster
  • *
  • Posts: 4
  • Respect: 0
  • School: St Joseph's College Geelong
  • School Grad Year: 2018
Re: Physics: Discussion, Questions & Potential Solutions
« Reply #32 on: November 14, 2018, 03:28:35 pm »
+1
My first 5 questions:

1a.) = 5x10^4 Vm^-1
b.) = 1.3x10^6 ms^-1
c.) = 0.57m

2a.) emf = 6.4x10^-4
b.) GRAPH = y position = 0 , (neg) , 0 , (pos) , 0

3a.) Clockwise
3b.) right hand slap rule

4a.) (bit confusing) = 2.8V (Vrms/root(2))??
4b.) GRAPH = (amp and frequency) x2

5a.) no idea... with this question  but 72W
5b.) 1.0V
5c.) 72W
5d.) 2W
5e.) she's safer



Richard Feynman 101

  • Forum Regular
  • **
  • Posts: 54
  • Respect: -12
Re: Physics: Discussion, Questions & Potential Solutions
« Reply #33 on: November 14, 2018, 03:29:36 pm »
0
My first 5 questions:

1a.) = 5x10^4 Vm^-1
b.) = 1.3x10^6 ms^-1
c.) = 0.57m

2a.) emf = 6.4x10^-4
b.) GRAPH = y position = 0 , (neg) , 0 , (pos) , 0

3a.) Clockwise
3b.) right hand slap rule

4a.) (bit confusing) = 2.8V (Vrms/root(2))??
4b.) GRAPH = (amp and frequency) x2

5a.) no idea... with this question  but 72W
5b.) 1.0V
5c.) 72W
5d.) 2W
5e.) she's safer

Looking good so far mate!  :P

izam25

  • Adventurer
  • *
  • Posts: 16
  • Respect: 0
Re: Physics: Discussion, Questions & Potential Solutions
« Reply #34 on: November 14, 2018, 03:33:49 pm »
0
How did u do the speaker question

I made a mistake without that question (gotta love exam conditions) but I just said that the second quiet region is the second node which on a standard wave form would be one wavelength away, forgetting that I should've used the pd formula (pd=(n-1/2)lamda) which would've been 1.5m

jpulvirenti

  • Adventurer
  • *
  • Posts: 21
  • Respect: 0
Re: Physics: Discussion, Questions & Potential Solutions
« Reply #35 on: November 14, 2018, 03:38:52 pm »
0
I made a mistake without that question (gotta love exam conditions) but I just said that the second quiet region is the second node which on a standard wave form would be one wavelength away, forgetting that I should've used the pd formula (pd=(n-1/2)lamda) which would've been 1.5m

I did that too.

Richard Feynman 101

  • Forum Regular
  • **
  • Posts: 54
  • Respect: -12
Re: Physics: Discussion, Questions & Potential Solutions
« Reply #36 on: November 14, 2018, 03:40:39 pm »
0
So the stupid spring question....

It states "the ball and spring come to rest when they are at a distance of 0.50 m below the uncompressed position of the spring."

To me, that sounds as if the ball and spring have stopped oscillating. Thus the forces are balanced, and mg = kx, and thus k = 39.2 N/m.

If it means the lowest point that the ball reaches, then it should have specified MOMENTARILY at rest. In which case you use an energy approach and you end up with k = 392 N/m. But the lack of the word MOMENTARILY changes the question completely.

Not to mention the rest of the question. Are we to assume that now the ball has stuck to the spring and is undergoing an oscillating motion? And we are to analyse the motion of the ball after it has stuck, disregarding the first part of the ball's motion? Because then the question makes sense. BUT NO WHERE DOES IT SAY TO DO THAT!

Rant over, sorry guys.

Difficultiy, confusion or frustration should never be confused with stupidity.

Spring question
(a)
k = 2mg∆h/(∆x)^2
= 2 • 2 • 9.8 • 2.5/ (0.5)^2
= 98/ 0.25
k = 392 N m^-1 (Q.E.D).

(b)
Common answer (reasonable) was 9.8 m s^-2 this is wrong however, actual and final answer is 0 m s^-2 since acceleration-mass system when max speed is reach is 0.

(c)
∆x for max speed. Max speed occurs at midpoint of compression, therefore, ∆x/2 = 0.5/2 = 0.25 m

PD was given so was wavelength, solve for n (n=4.0082),

Speaker
Wavelength = 1m (v=fwavlength).

Transmission questions were misleading since current in lines in normally what you would calculate first and then progress to the power loss questions. Anyhow, this would be answered terrible, overall, harder than last years as expected (first year study design) is always easier, but nevertheless 2018 class is all in this together.

Love, the zero gravity questions  :o

izam25

  • Adventurer
  • *
  • Posts: 16
  • Respect: 0
Re: Physics: Discussion, Questions & Potential Solutions
« Reply #37 on: November 14, 2018, 03:41:00 pm »
0
I did that too.

It was only like 2 marks right lolll rip

matthewmwps

  • Adventurer
  • *
  • Posts: 16
  • Respect: 0
Re: Physics: Discussion, Questions & Potential Solutions
« Reply #38 on: November 14, 2018, 03:42:41 pm »
0
what did everyone do for the "Find the Kinetic energy of the electrons" part of question 18?

Richard Feynman 101

  • Forum Regular
  • **
  • Posts: 54
  • Respect: -12
Re: Physics: Discussion, Questions & Potential Solutions
« Reply #39 on: November 14, 2018, 03:43:18 pm »
0
I made a mistake without that question (gotta love exam conditions) but I just said that the second quiet region is the second node which on a standard wave form would be one wavelength away, forgetting that I should've used the pd formula (pd=(n-1/2)lamda) which would've been 1.5m

Yeah mate, its quiet because of destrcutive interference (crest meet trough, ampltiude cancel out), therefore, node.

Richard Feynman 101

  • Forum Regular
  • **
  • Posts: 54
  • Respect: -12
Re: Physics: Discussion, Questions & Potential Solutions
« Reply #40 on: November 14, 2018, 03:45:05 pm »
0
what did everyone do for the "Find the Kinetic energy of the electrons" part of question 18?

Ek = (lorentz - 1) rest mass • c^2

jpulvirenti

  • Adventurer
  • *
  • Posts: 21
  • Respect: 0
Re: Physics: Discussion, Questions & Potential Solutions
« Reply #41 on: November 14, 2018, 03:45:58 pm »
0
Difficultiy, confusion or frustration should never be confused with stupidity.

Spring question
(a)
k = 2mg∆h/(∆x)^2
= 2 • 2 • 9.8 • 2.5/ (0.5)^2
= 98/ 0.25
k = 392 N m^-1 (Q.E.D).

(b)
Common answer (reasonable) was 9.8 m s^-2 this is wrong however, actual and final answer is 0 m s^-2 since acceleration-mass system when max speed is reach is 0.

(c)
∆x for max speed. Max speed occurs at midpoint of compression, therefore, ∆x/2 = 0.5/2 = 0.25 m

PD was given so was wavelength, solve for n (n=4.0082),

Speaker
Wavelength = 1m (v=fwavlength).

Transmission questions were misleading since current in lines in normally what you would calculate first and then progress to the power loss questions. Anyhow, this would be answered terrible, overall, harder than last years as expected (first year study design) is always easier, but nevertheless 2018 class is all in this together.

Love, the zero gravity questions  :o
[/quoin the transmission question, was the current given for the lines or for the current the ligh uses after transformer

izam25

  • Adventurer
  • *
  • Posts: 16
  • Respect: 0
Re: Physics: Discussion, Questions & Potential Solutions
« Reply #42 on: November 14, 2018, 03:46:49 pm »
+1
Yeah mate, its quiet because of destrcutive interference (crest meet trough, ampltiude cancel out), therefore, node.

Yeah that wasn't the bit I mixed up lmao

matthewmwps

  • Adventurer
  • *
  • Posts: 16
  • Respect: 0
Re: Physics: Discussion, Questions & Potential Solutions
« Reply #43 on: November 14, 2018, 03:47:53 pm »
0
the first part of question 5 was confusing for sure, but i found it easy once I figured out the trick.

You just need to use
I(2)/I(1)=N1/N2
with I1=3, N1/N2=4
then you get I2 (current going to globe) = 3*4->12 A
then just use P=IV to get a power of 48 watts

A quick way to test your answer is to see if the power at the globe and your power loss over the lines add up to your total power
(in this case, 48+24=72)

matthewmwps

  • Adventurer
  • *
  • Posts: 16
  • Respect: 0
Re: Physics: Discussion, Questions & Potential Solutions
« Reply #44 on: November 14, 2018, 03:48:59 pm »
+2
Ek = (lorentz - 1) rest mass • c^2

Wasn't that a completely different question?
I meant the one with the two diffraction patterns