Physics: Discussion, Questions & Potential Solutions

[Seno72]

Hey lads, ehat did you have as the undertainty for the voltmeter in the mcq?

[izam25]

Hey lads, ehat did you have as the undertainty for the voltmeter in the mcq?

I had 0.5 A because the 'fineness' of the scale was 1A so I think the uncertainty would be +/- 0.5A

[S200]

What did people say about the "must the spaceship be an inertial reference frame" question?

The question mentioned that the ship was travelling at a constant speed, not velocity, so the ship may be an inertial reference frame if travelling in a straight line, but it doesn't have to be in the case of travelling in a circular path, which still has constant speed.

1.) The ship was not accelerating, so that rules out centripetal activity...

2.) The ship itself is not in an inertial frame of reference,  but the people inside the ship were...

[Bri MT]

1.) The ship was not accelerating, so that rules out centripetal activity...

2.) The ship itself is not in an inertial frame of reference,  but the people inside the ship were...

The question does not state that the ship is not accelerating. It says that the person is stationary and that the ship is moving at a constant speed

[MrTeacherMan]

1.) The ship was not accelerating, so that rules out centripetal activity...

2.) The ship itself is not in an inertial frame of reference,  but the people inside the ship were...

I disagree with the first point. The question didn’t specify that there was no acceleration, only that it was travelling at constant speed. Constant speed is still possible under uniform circular motion. Constant speed does not imply constant velocity.

[wanigara]

Multi Choice Answers:
(1) B (2) A (3) A (4) D (5) C (6) C (7) A ( C (9) B (10) D (11) D (12) C (13) D (14) B (15)D (16) C (17) A (18) A (19) B (20) B

[Freddie Hg]

Multi Choice Answers:
(1) B (2) A (3) A (4) D (5) C (6) C (7) A ( C (9) B (10) D (11) D (12) C (13) D (14) B (15)D (16) C (17) A (18) A (19) B (20) B

i think 7 is b? it was just divided by 4. idk im doing this by memory

[mzhao]

i think 7 is b? it was just divided by 4. idk im doing this by memory

The question asked for the gravitational field strength when distance is increased BY 2R, not to 2R.

[Freddie Hg]

what was the momentum mcq answer??

[Freddie Hg]

The question asked for the gravitational field strength when distance is increased BY 2R, not to 2R.

yeah so divided by 4? idk what  2R, not to 2R. means

[Bri MT]

The question asked for the gravitational field strength when distance is increased BY 2R, not to 2R.

It asked for the field strength at a distance 2R above Earth's surface
 

[wanigara]

Short Answers
Q1 (a) E = V/d = 5.0x10^4 Vm-1 (b) W= qV = 1/2mV2 = 1.4x10^6 ms-1 (c) r=mv/qB = 0.53 m

[Freddie Hg]

It asked for the field strength at a distance 2R above Earth's surface

my teacher also divided by 4. so idk, but can you guys explain (ive done a trial mcq and the same concept was tested, i got it wrong so you guys are more likely correct) 

[wanigara]

i think 7 is b? it was just divided by 4. idk im doing this by memory

Distance R (from the centre) is on the surface of the earth g= 9.76 N/kg. Then question asked the g value for a point 2R from the surface which is 3R from the centre. So new g is 1/9 * (9.76) = 1.08 N/kg .. using Inverse Square Law.

[Freddie Hg]

Distance R (from the centre) is on the surface of the earth g= 9.76 N/kg. Then question asked the g value for a point 2R from the surface which is 3R from the centre. So new g is 1/9 * (9.76) = 1.08 N/kg .. using Inverse Square Law.

damn thought i was gonna get 50