Some Math Help please

[aspiringantelope]

I did
3(4y-5)-2y-1=6y
12y-15-2y-1=6y
10y-16=6y
y=4?

[Lear]

You are forgetting the bracket around -(2y-1) which when you expand becomes -2y+1

[aspiringantelope]

You are forgetting the bracket around -(2y-1) which when you expand becomes -2y+1

OHHHHHHHHHH
THANKSS!!! woweeee
I thought you didn't need brackets after u cancel.

[Bri MT]

OHHHHHHHHHH
THANKSS!!! woweeee
I thought you didn't need brackets after u cancel.

When you look at a fraction a+c/d   with the divison line under both a and c
it's always (a+c)/d

[aspiringantelope]

Hopefully I didn't mess that up - with any luck it should be ok

@RuiAce
Are you allowed to divide (a+b) from both sides? From both xc(a+b) =  x(a+b)(a-b) - ab(a+b) ??
so it equals xc = x(a-b)-ab?

[Bri MT]

@RuiAce
Are you allowed to divide (a+b) from both sides? From both xc(a+b) =  x(a+b)(a-b) - ab(a+b) ??
so it equals xc = x(a-b)-ab?

I'm not Rui, but yes you are.

Remember that a+b is just some number

[aspiringantelope]

I'm not Rui, but yes you are.

Remember that a+b is just some number

Ok thanks, I just thought because it was -ab(a+b) so you wouldn't be allowed to

[Bri MT]

Ok thanks, I just thought because it was -ab(a+b) so you wouldn't be allowed to

-ab(a+b) is just
-1 times a times b times a+b
you can divide it by any of those things if you so chose.

You can expand -ab(a+b) to -ba^2 -ab^2   if you want (but we don't because it's not useful for us to do that), and this demonstrates that it's good to become familiar with factorising things as it can help you find solutions.

[aspiringantelope]

-ab(a+b) is just
-1 times a times b times a+b
you can divide it by any of those things if you so chose.

You can expand -ab(a+b) to -ba^2 -ab^2   if you want (but we don't because it's not useful for us to do that), and this demonstrates that it's good to become familiar with factorising things as it can help you find solutions.

Ok, thanks for the clarification @miniturtle !