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April 02, 2026, 07:24:02 am

Author Topic: Suggested Solutions [Core] - Exam 1  (Read 4128 times)  Share 

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tiff

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Re: Suggested Solutions [Core] - Exam 1
« Reply #15 on: November 02, 2009, 07:17:10 pm »
lol thanks. yeah i was a bit confused cos i couldn't work it out by hand, so i just used my calculator =) i got +102.

rustic_metal

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Re: Suggested Solutions [Core] - Exam 1
« Reply #16 on: November 02, 2009, 07:19:45 pm »
lol thanks. yeah i was a bit confused cos i couldn't work it out by hand, so i just used my calculator =) i got +102.
Same. :)

lachymm

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Re: Suggested Solutions [Core] - Exam 1
« Reply #17 on: November 03, 2009, 12:07:22 am »
Ur reading into alot man...Its further :D
2009 Further Mathematics [41]

Enter 95+

manda2290

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Re: Suggested Solutions [Core] - Exam 1
« Reply #18 on: November 03, 2009, 07:59:45 am »
did anyone do modules 3 and 6...
and have the answers????

rezal

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Re: Suggested Solutions [Core] - Exam 1
« Reply #19 on: November 03, 2009, 10:16:49 am »
Question 8 is E i believe

look i put C for that one. It seemed to me one of those questions where 70% pick one answer (E) but are all wrong.
the wording was poor. But ive looked at it many times since the exam. In the exam i was sure it was C, so i put C. And having looked at it again id still say C. It was very careful in the way it was worded. It said "what percentage of animals whose bla blah bla and whose bla bla bla" causing me to question why it would want only one column and not the 86% specified over all three columns. Also, there were three columns, so why would it only involve one column. 86/300 was my first thought. Which meant it was closest to C.

I made some terrible other errors. kinda embarrassing to admit ha. looking at 36-37. Looking forward to Wednesday though :) Good luck to everyone

pbesson

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Re: Suggested Solutions [Core] - Exam 1
« Reply #20 on: November 03, 2009, 12:21:13 pm »
module 1 question 9 i got D cus n=9 and not 10. you only count the distance between checkpoints as terms in the sequence? that's how i did it at least..

Nope
Its
Sum(10)=4500=5(2a+450)
therefore a=225=difference b/w checkpoint 1 and 2
225+50=275=distance b/w checkpoint 2 and 3

how can the difference end in a 5???
if you continue to add 50 for each checkpoint it will never reach an even number therefore it will never be 4500 metres because that doesn't end in a 5!!!

i believe the answer is D

stonecold

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Re: Suggested Solutions [Core] - Exam 1
« Reply #21 on: November 03, 2009, 06:49:28 pm »
module 1 question 9 i got D cus n=9 and not 10. you only count the distance between checkpoints as terms in the sequence? that's how i did it at least..

Nope
Its
Sum(10)=4500=5(2a+450)
therefore a=225=difference b/w checkpoint 1 and 2
225+50=275=distance b/w checkpoint 2 and 3

Unfortunately you have miscalculated. There are only 9 intervals between Checkpoints 1 and 10. You have done your calculation based on 10 intervals.  This is the correct answer.  Unfortunately, I only came to the realisation after I walked out of the exam room :(

Module 1 : Question 9

Find a, the first term.

4500=9/2(2a+8x50)

a=300

t1 is between checkpoint 1 and 2
t2 is between checkpoint 2 and 3

t2 = t1 +50 = 300 + 50 = 350 meters - Answer D
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VCE 2009'10: English 46 | English Language 49 | Chemistry 50 | Biology 50 | Further Mathematics 48 | Mathematical Methods CAS 39
ATAR: 99.85

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