i'm so sorry! i meant question 7 from geometry and trigonometry.
First you have to find the length of the diagonal RC. To do this, you use Pythagoras.
So:
c2 (RC) = a2 + b2
RC = square root of (3.8 squared + 12 squared)
RC = 12.59 m.
You now have to find angle ACR. This triangle has AR (length of 1.5m) and RC (length of 12.59m). We are trying to find the angle ACR, and we only have two sides with lengths on them. These sides are Opposite to the angle we are trying to the find, and Adjacent to it. Therefore we use the old 'SOH-CAH-TOA' to find that we have to use Tan to solve this. Remember that if we are trying to find the angle, we use INVERSE tan.
So:
Angle ACR = tan-1 (Opposite/Adjacent)
Angle ACR = tan-1 (1.5/12.59)
Angle ACR = 6.79
....which is closest to 6.80 (A).
Hope that helps etc.