How to graph the hyperbola of y=1/x-1?
Normally when it is like y=-1/2x+5 I know how to graph it but when the last value(5 or any number) is missing I do not know how to graph it
Thanks in advance!
Hey Rose,
x-1 simply means a horizontal shift on the x-axis to the right by 1 unit.
You usually equate the bottom part of the fraction to 0 and solve for x, to find the vertical asymptote.
So your vertical asymptote will be at x=1
For your other example of y=-1/2x+5
Your vertical asymptote will be at
2x+5=0
Therefore x= -5/2
Back to your original question, of y=1/x-1
The horizontal asymptote would be 0.
Edit: Forgot to mention, if you want to find your y-intercept, then let x=0
So y=1/0-1
y = -1
Therfore your y-intercept is (0,-1)
For your x-intercept you let y=0.
Therefore in this graph, there is no x-intercept
Knowing this you can graph your hyperbola, it should look something like:

(make sure your hyperbolae never touch the vertical and horizontal asymptotes)
I hope this helped, also use this website called desmos to play around with graphs and see what they would look like, it really helps (here's the link:
https://www.desmos.com/calculator