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October 08, 2025, 08:02:42 am

Author Topic: Methods 2009 Exam 1 Suggested Solutions  (Read 23300 times)  Share 

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Gloamglozer

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Re: Methods 2009 Exam 1 Suggested Solutions
« Reply #135 on: November 06, 2009, 02:36:20 pm »
For the expected value function, I left it as 12/10 instead of reducing it to 6/5 or 1.2.  Does anyone know if I'll lost an answer mark for that?

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YT_17

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Re: Methods 2009 Exam 1 Suggested Solutions
« Reply #136 on: November 06, 2009, 02:40:35 pm »
Hey, sorry itute answer has 1b simplified......that means u need to simplify?

steph_r

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Re: Methods 2009 Exam 1 Suggested Solutions
« Reply #137 on: November 06, 2009, 02:47:07 pm »
anyone know what approximate study score this would get:
High A+ sacs
High B+ exam1
B+ exam 2

squance

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Re: Methods 2009 Exam 1 Suggested Solutions
« Reply #138 on: November 06, 2009, 02:51:51 pm »
My sis reckons she got 36/40 for methods. She stuffed up the first part to question 2. :S

matthew_potato

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Re: Methods 2009 Exam 1 Suggested Solutions
« Reply #139 on: November 06, 2009, 03:14:36 pm »
soz for reposting this, i posted b4 but no answer:

for the last question i said that the approx formula was an existing val (2) + the area (rectangle) under the differential curve that is (f'(8) x h). where h is the width, i then drew a differential graph (no tangents) with the area shown and stated that because the approx area is bigger, the approx value was bigger then original

it's not what the answers say, but do you think i'll get the mark? or is what i wrote even true?

NE2000

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Re: Methods 2009 Exam 1 Suggested Solutions
« Reply #140 on: November 06, 2009, 03:16:43 pm »
yeah I don't think what you say is actually true. It doesn't actually use the area, it uses tangents :S
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matthew_potato

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Re: Methods 2009 Exam 1 Suggested Solutions
« Reply #141 on: November 06, 2009, 03:19:56 pm »
yeah I don't think what you say is actually true. It doesn't actually use the area, it uses tangents :S

hmm, true,, didn't really have any idea how to answer that so i just made up something that sounded "right" lol, oh well, 37/40's not bad yeah?

nala

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Re: Methods 2009 Exam 1 Suggested Solutions
« Reply #142 on: November 06, 2009, 03:21:41 pm »
37/40 is good! That's either really high A or low A+ depending on the grade distributions. :)

matthew_potato

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Re: Methods 2009 Exam 1 Suggested Solutions
« Reply #143 on: November 06, 2009, 03:30:32 pm »
37/40 is good! That's either really high A or low A+ depending on the grade distributions. :)

yeah,,, just as long as its not like the physics midyear :P

makemytime

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Re: Methods 2009 Exam 1 Suggested Solutions
« Reply #144 on: November 06, 2009, 03:37:17 pm »
37/40 is good! That's either really high A or low A+ depending on the grade distributions. :)

yeah,,, just as long as its not like the physics midyear :P

yeah.... 95% was minimum for A+... :( i had 90% and it was only an A

just wondering, for question 2a) if i did not place modulus signs, would i lose a mark?

TrueTears

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Re: Methods 2009 Exam 1 Suggested Solutions
« Reply #145 on: November 06, 2009, 03:41:42 pm »
Yeah I'd say for people who didn't place mod signs you'd lose a mark. Must have mod signs when anti-diffing to a log unless you know that the expression inside the log can never be smaller than 0.
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simpak

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Re: Methods 2009 Exam 1 Suggested Solutions
« Reply #146 on: November 06, 2009, 04:00:13 pm »
The mod sign is even on the formula sheet.
If they give it to you that way, then that's the way they'd want it when you apply the formula.
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dcc

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Re: Methods 2009 Exam 1 Suggested Solutions
« Reply #147 on: November 06, 2009, 04:13:06 pm »
I see a 'clearly' in one of the proofs - how amusing.  I'm sure VCAA won't mind though.  Perhaps it is clear?

nels

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Re: Methods 2009 Exam 1 Suggested Solutions
« Reply #148 on: November 06, 2009, 04:13:27 pm »
i got 5b(the four identical balls question)  incorrect, does that mean that i wont get full marks for 5c even though my working out was correct?

nala

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Re: Methods 2009 Exam 1 Suggested Solutions
« Reply #149 on: November 06, 2009, 04:22:22 pm »
I'm pretty sure you will get the method mark, but not the answer mark.