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September 25, 2025, 06:40:25 pm

Author Topic: Questions thread  (Read 19082 times)  Share 

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Cataclysmic

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Re: Questions thread
« Reply #75 on: December 08, 2009, 02:28:26 pm »
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lol failed use of latex ;d
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Ilovemathsmeth

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Re: Questions thread
« Reply #76 on: December 08, 2009, 02:30:51 pm »
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For 1. a) Here's how you'd do it the long way. I'm terrible with using LaTex by the way :P

is the new image.







This gives the same result; a dilation of factor 2 from the x-axis, a translation of 3 units in the positive direction of the y-axis and a translation of 1 unit in the positive direction of the x-axis.

Hope that helps.

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Ilovemathsmeth

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Re: Questions thread
« Reply #77 on: December 08, 2009, 02:31:34 pm »
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Ahh really, did it fail?? :(
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Hielly

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Re: Questions thread
« Reply #78 on: December 09, 2009, 12:38:50 pm »
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For 1. a) Here's how you'd do it the long way. I'm terrible with using LaTex by the way :P

is the new image.







This gives the same result; a dilation of factor 2 from the x-axis, a translation of 3 units in the positive direction of the y-axis and a translation of 1 unit in the positive direction of the x-axis.

Hope that helps.



hey for this
How did you get this?, you rearraged it in the form of y=1/x

when i did thi i got y'-3=2/(x-1) and if use cross multiply then (y'-3)(x-1)/2 ?

Ilovemathsmeth

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Re: Questions thread
« Reply #79 on: December 09, 2009, 01:33:15 pm »
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Nah, you're dividing both sides by 2 from the step:

to give

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Hielly

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Re: Questions thread
« Reply #80 on: December 09, 2009, 01:35:35 pm »
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ok thanks how would you do q1f ?
In each case below, state the sequence of transformations required to transform the graph
of the first equation into the graph of the second equation:
y =2/3 − x + 4, y =1/x

Ilovemathsmeth

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Re: Questions thread
« Reply #81 on: December 09, 2009, 01:37:25 pm »
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Which post was it?
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Hielly

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Re: Questions thread
« Reply #82 on: December 09, 2009, 01:46:06 pm »
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and this, not sure how to sketch it in this equation format

thanks

Cataclysmic

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Re: Questions thread
« Reply #83 on: December 09, 2009, 05:48:12 pm »
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It tells you that .

You know that is a rectangular hyperbola and using transformations you can see:
It is reflected in the x-axis
It is translated 1 unit to the left
It is translated 3 units up.

And there is an asymptote at ( because it would be make the denominator 0, making the equation undefined) and (would give you ........ 
« Last Edit: December 09, 2009, 05:52:39 pm by Cataclysmic »
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Ilovemathsmeth

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Re: Questions thread
« Reply #84 on: December 09, 2009, 06:45:58 pm »
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To sketch such an equation, do long division to convert it into the more familiar hyperbolic function and then sketch in the normal way, finding asymptotes and then intercepts.
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qshyrn

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Re: Questions thread
« Reply #85 on: December 09, 2009, 07:54:46 pm »
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hielly , i hope u dont mind if i post a quick question of my own here :P(if u do mind, then let me know and ill delete this post)

when finding out general solutions for trig equations, would we lose marks for not following the conventions, that is:
has range
has range
has range
for example: the general solution to
would writing "" be alright, or does it have to be
« Last Edit: December 09, 2009, 08:03:46 pm by qshyrn »

TrueTears

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Re: Questions thread
« Reply #86 on: December 09, 2009, 07:58:30 pm »
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is fine.
PhD @ MIT (Economics).

Interested in asset pricing, econometrics, and social choice theory.

kenhung123

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Re: Questions thread
« Reply #87 on: December 10, 2009, 12:53:20 am »
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Nah, you're dividing both sides by 2 from the step:

to give


Can you please demonstrate how you would find the dilation factor on y=1/x to produce 1/2x? In the example you did, did you divide it by 2 because you knew it was from the x axis or it is convention?

kenhung123

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Re: Questions thread
« Reply #88 on: December 10, 2009, 01:08:03 am »
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When sketching the graph of a truncus, is it necessary to use arrows?

Ilovemathsmeth

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Re: Questions thread
« Reply #89 on: December 10, 2009, 01:42:41 am »
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It might be a good idea actually to have arrows. I think they took a mark off me once in 1/2 or yr 10 Maths for not having arrows. Maybe they were just tight :P

In that case, it's already in the form







This suggests a dilation of factor 1/2 from the y-axis as it affects the x-values. You could also have done this by inspection, as it appears to be of the form suggesting a dilation of 1/k from the y-axis, in this case 1/2. Hope that helps.
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