I have not touched this type of Chemistry in 3 years, but here's my best effort

From the graph, we see that the diluted solution's 250 arbitrary units of peak area corresponds to roughly 5% v/v ethanol.
But that's of the DILUTED solution. We now have to work out the dilution factor of the solution being tested.
Remember that they took 20 mL of whiskey and added 180 mL of water.
Remembering that

, the
amount of whiskey in the sample
will not change, and only its concentration from undiluted to diluted will. Applying this principle of conservation of mass (amount of stuff), we see that

We know that

(converted 20 mL = 0.02L), and we know that

Thus, plugging this in,

and so,

Which means that the dilution factor is 10. This makes sense that if you dilute a sample from 20 mL to 200mL (increase volume by 10 times), then the concentration decreases by a factor of 10.
So as we worked out from the graph,

therefore,

% v/v
If I got this wrong I am going to cry and just stick to the maths boards
