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May 15, 2025, 05:48:34 pm

Author Topic: 1,000,000 Question Thread :D  (Read 10787 times)  Share 

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kenhung123

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Re: 1,000,000 Question Thread :D
« Reply #75 on: December 21, 2009, 05:14:50 pm »
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Fundamental THANKS!

kenhung123

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Re: 1,000,000 Question Thread :D
« Reply #76 on: December 21, 2009, 08:53:10 pm »
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Is this reduction: 2I- => I2+2e  ?

kenhung123

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Re: 1,000,000 Question Thread :D
« Reply #77 on: December 21, 2009, 08:58:24 pm »
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When it lose elections shouldn't it be oxidation?

Edmund

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Re: 1,000,000 Question Thread :D
« Reply #78 on: December 21, 2009, 09:27:01 pm »
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Oxidation is the loss of electrons:

E.g.

Reduction is gain:

E.g.

Is this reduction: 2I- => I2+2e  ?
Oxidation
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kenhung123

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Re: 1,000,000 Question Thread :D
« Reply #79 on: December 21, 2009, 09:32:06 pm »
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Oxidation is the loss of electrons:

E.g.

Reduction is gain:

E.g.

Is this reduction: 2I- => I2+2e  ?
Oxidation
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Ilovemathsmeth

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Re: 1,000,000 Question Thread :D
« Reply #80 on: December 22, 2009, 01:04:55 am »
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Reduction occurs when there is a decrease in oxidation number. So in the above case, the O.N changes from -1 to 0 - i.e. there is an increase in O.N, so it is oxidation not reduction.
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stonecold

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Re: 1,000,000 Question Thread :D
« Reply #81 on: December 22, 2009, 02:49:01 am »
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AN OIL RIG CAT
Oxidation is Loss of Electrons and occurs at the anode.
Reduction is Gain of electrons and occurs at the cathode.

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Ilovemathsmeth

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Re: 1,000,000 Question Thread :D
« Reply #82 on: December 22, 2009, 11:33:55 am »
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They are pretty helpful. :)
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kenhung123

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Re: 1,000,000 Question Thread :D
« Reply #83 on: December 22, 2009, 01:02:26 pm »
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How does the H+ cancellation work?

E.g.

X + Y + 7H+ => Y + X + 2H+

Would it be:

X + Y + 5H+ => Y + X ?

Potter

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Re: 1,000,000 Question Thread :D
« Reply #84 on: December 22, 2009, 01:17:16 pm »
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How does the H+ cancellation work?

E.g.

X + Y + 7H+ => Y + X + 2H+

Would it be:

X + Y + 5H+ => Y + X ?

Yeah, that's pretty much it, you do the same thing when you have water on both sides of the equation. Don't just apply that to H+'s
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kenhung123

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Re: 1,000,000 Question Thread :D
« Reply #85 on: December 22, 2009, 01:20:00 pm »
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So you just minus the large from the small and add it to the side which the large is from?

kyzoo

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Re: 1,000,000 Question Thread :D
« Reply #86 on: December 22, 2009, 01:32:34 pm »
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It's just like algebra
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kenhung123

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Re: 1,000,000 Question Thread :D
« Reply #87 on: December 22, 2009, 02:30:52 pm »
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Thank you

kenhung123

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Re: 1,000,000 Question Thread :D
« Reply #88 on: December 25, 2009, 04:02:53 am »
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1. A sample of brown dye from a lolly is placed at the origin on a strip of chromatography paper. The solvent front moves up 9.0cm from the origin. A blue component of the dye moves 7.5cm and a red compoenent 5.2cm in the same time. Calculate the Rf values of the 2 components.

(I got Rf blue as 0.83 and Rf red as 0.58)
2. A sample of brown dye used in a brand of writing ink was found to contain blue and yellow components. The Rf values of these substrances using ethanol as a solvent are 0.59 and 0.19 respectively.

How far apart would the blue and yellow componenets be after the solvent front has move 8.0cm from the origin?
(I got 3.2cm)

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Re: 1,000,000 Question Thread :D
« Reply #89 on: December 25, 2009, 10:35:17 am »
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You're correct?
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