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January 02, 2026, 01:55:58 pm
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Author Topic: Bucket's Questions  (Read 56965 times)  Share 

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Glockmeister

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Re: Bucket's Questions
« Reply #105 on: March 08, 2008, 10:26:31 pm »
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Quote from: Mao on March 08, 2008, 08:46:12 pm
if you multiplied by two on both sides:



then take log2 on both sides







:D didnt even touch rational functions :D



That's not 100% simplifed. There's still x'es on both sides.
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Mao

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Re: Bucket's Questions
« Reply #106 on: March 08, 2008, 10:31:55 pm »
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pssst here u go:





kk? :P

or
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Re: Bucket's Questions
« Reply #107 on: March 09, 2008, 03:41:47 am »
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Neobeo

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Re: Bucket's Questions
« Reply #108 on: March 09, 2008, 07:26:57 am »
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But really, Mao has some careless arithmetical errors, which should actually give:
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Mao

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Re: Bucket's Questions
« Reply #109 on: March 09, 2008, 11:38:14 am »
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oh gar.... i dont know how to divide two by three... :(

if you multiplied by two on both sides:



then take log2 on both sides




















LOL at myself...
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Glockmeister

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Re: Bucket's Questions
« Reply #110 on: March 09, 2008, 02:12:32 pm »
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Can anyone else spot any errors in Mao's working? lol
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[22:07] <robbo> i luv u Glockmeister

<Glockmeister> like the people who like do well academically
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<%Neobeo> sounds like Ahmad0
<@Ahmad0> no
<@Ahmad0> sounds like Neobeo

2007: Mathematical Methods 37; Psychology 38
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Re: Bucket's Questions
« Reply #111 on: March 09, 2008, 02:41:49 pm »
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Quote from: Glockmeister on March 09, 2008, 02:12:32 pm
Can anyone else spot any errors in Mao's working? lol
bah it's right this time k???!

:'(
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bucket

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Re: Bucket's Questions
« Reply #112 on: March 09, 2008, 09:39:57 pm »
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Ok I have no idea how to work this kind of question out without using a calculator:

b) find the points of intersection of the graphs y=f(x) and y=f -1(x)


and I worked out the inverse to be
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ed_saifa

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Re: Bucket's Questions
« Reply #113 on: March 09, 2008, 09:41:04 pm »
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find the intersection with line y=x i think
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Re: Bucket's Questions
« Reply #114 on: March 09, 2008, 09:42:50 pm »
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how do i do that?
do I sketch them both?
=_=
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ed_saifa

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Re: Bucket's Questions
« Reply #115 on: March 09, 2008, 09:46:51 pm »
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maybe. but if you're not supposed to use a calculator, then your going to have to solve it by hand.
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"How can you expect to do well when
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"Why'd you score so bad?!" - Zotos
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bucket

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Re: Bucket's Questions
« Reply #116 on: March 09, 2008, 09:49:20 pm »
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Yeah...

It doesn't say I can't use a calculator, but I want to know how to solve it without one, if there is a way
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ed_saifa

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Re: Bucket's Questions
« Reply #117 on: March 09, 2008, 09:49:59 pm »
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i have no clue. i can't seem to manipulate the algebra to get x by itself. sorry
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"It's not allowed. Only death is a valid excuse"
"Probably for the first time time this year I was totally flabbergasted by some of the 'absolute junk' I had to correct .... I was going to use 'crap' but that was too kind a word"
"How can you expect to do well when
-you draw a lemon as having two half-cells connected with a salt bridge
-your lemons come with Cu2+ ions built in" - Dwyer
"Why'd you score so bad?!" - Zotos
"Your arguments are seri

Glockmeister

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Re: Bucket's Questions
« Reply #118 on: March 09, 2008, 09:50:46 pm »
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No, you let

i.e
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"this post is more confusing than actual chemistry.... =S" - Mao

[22:07] <robbo> i luv u Glockmeister

<Glockmeister> like the people who like do well academically
<Glockmeister> tend to deny they actually do well
<%Neobeo> sounds like Ahmad0
<@Ahmad0> no
<@Ahmad0> sounds like Neobeo

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Re: Bucket's Questions
« Reply #119 on: March 09, 2008, 09:52:34 pm »
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I don't think you can solve analytically. You could use Newton's method to approximate the solutions (http://en.wikipedia.org/wiki/Newton's_Method) however that is time-consuming and messy.
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