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December 30, 2025, 09:20:56 pm
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Author Topic: Bucket's Questions  (Read 56803 times)  Share 

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lwine

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Re: Bucket's Questions
« Reply #195 on: June 22, 2008, 10:26:40 pm »
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The tangent is always a straight line in the form

To find , the gradient, we must differentiate and find the instantaneous rate of change at the given point.







To find , we can substitute in the ordered pair at that point:






Therefore, the tangent is:
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bucket

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Re: Bucket's Questions
« Reply #196 on: June 22, 2008, 10:45:09 pm »
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ah thanks a tonne =]
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bucket

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Re: Bucket's Questions
« Reply #197 on: June 24, 2008, 12:45:40 am »
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Find for which is divisible by but not .
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Glockmeister

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Re: Bucket's Questions
« Reply #198 on: June 24, 2008, 01:00:15 am »
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Basically (because it's late)

You let the function P(2)=0 i.e let x=2, and the equation equal zero.
Then you let P(1)=0 and then reject the solution of the P(2)=0 that matches the solution in P(1)=0
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bucket

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Re: Bucket's Questions
« Reply #199 on: June 24, 2008, 01:27:35 am »
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oh, never thought of that.. thanks alot man =]
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Glockmeister

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Re: Bucket's Questions
« Reply #200 on: June 24, 2008, 05:16:42 pm »
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Someone asked a similar question a few months before actually, I just couldn't find the post.
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"this post is more confusing than actual chemistry.... =S" - Mao

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bucket

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Re: Bucket's Questions
« Reply #201 on: June 24, 2008, 09:49:34 pm »
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Prove that is divisible by for all values of k.

How would you show this :s.
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Mao

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Re: Bucket's Questions
« Reply #202 on: June 24, 2008, 10:19:08 pm »
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Quote from: bucket on June 24, 2008, 09:49:34 pm
Prove that is divisible by for all values of k.

How would you show this :s.

try subbing in :)
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bucket

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Re: Bucket's Questions
« Reply #203 on: June 24, 2008, 10:20:05 pm »
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 :uglystupid2: I solved it incorrectly when I did it myself :s.
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Flaming_Arrow

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Re: Bucket's Questions
« Reply #204 on: June 24, 2008, 10:44:31 pm »
0










epic phail
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bucket

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Re: Bucket's Questions
« Reply #205 on: June 24, 2008, 11:11:00 pm »
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lol i wrote it incorrectly.
it's (k-1)

epic fail to me.
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Flaming_Arrow

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Re: Bucket's Questions
« Reply #206 on: June 24, 2008, 11:24:36 pm »
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Quote from: bucket on June 24, 2008, 11:11:00 pm
lol i wrote it incorrectly.
it's (k-1)

epic fail to me.

in that case











k's will cancel out hence the value k is negligible



« Last Edit: June 24, 2008, 11:27:25 pm by chath »
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bucket

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Re: Bucket's Questions
« Reply #207 on: June 24, 2008, 11:25:37 pm »
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yeah i worked it out after realising it was k-1.
thanks anyway lol.
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Flaming_Arrow

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Re: Bucket's Questions
« Reply #208 on: June 24, 2008, 11:27:42 pm »
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Quote from: bucket on June 24, 2008, 11:25:37 pm
yeah i worked it out after realising it was k-1.
thanks anyway lol.

lol np im bored so yer xD
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bucket

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Re: Bucket's Questions
« Reply #209 on: July 24, 2008, 08:01:01 pm »
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The curve for is such that the tangent at passes through the origin. find the gradient of the tangent and hence determine:
a. The value of K
b. The equation of the curve.
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