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January 13, 2026, 10:59:56 am

Author Topic: Bucket's Questions  (Read 57611 times)  Share 

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bucket

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Re: Bucket's Questions
« Reply #330 on: November 05, 2008, 10:51:33 pm »
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they take up like 10 fucking minutes and then i end up getting them wrong anyway =_= lol
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dekoyl

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Re: Bucket's Questions
« Reply #331 on: November 05, 2008, 10:59:32 pm »
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Mmm, whenever I do a trial exam I always fuck up when i need to manually plot a trig graph. Does anybody have any tricks for doing these? I have the most difficulty determining endpoints and the y intercept whenever the graph is translated in any direction.
I have troubles with the y-ints as well. I sometimes have trouble seeing if the maximum occurs on the right or left side of the y-axis.

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Re: Bucket's Questions
« Reply #332 on: November 05, 2008, 11:00:38 pm »
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Mmm, whenever I do a trial exam I always fuck up when i need to manually plot a trig graph. Does anybody have any tricks for doing these? I have the most difficulty determining endpoints and the y intercept whenever the graph is translated in any direction.

I think it gets easier when you split it up into different steps. For instance, I would normally do:

If ,

- I will lightly draw the lines y = d, y = d+a, y = d-a on the graph paper. This gives me boundaries which I cannot step over, as well as the middle.

- Then I solve f(x) = 0 for x, marking in the intercept points. (I generally find this the hardest part of graphing; not so much the solving, but more the scaling of the graph) A neat trick is if d = 0, then the solutions will be away from each other. You can also work these out by applying transformations to your standard graph of .

- Plug x in for endpoints and y-intercept, marking these points on the graph. (I would have thought this would be a simpler step o.O)

- Now it's a simple game of connect the dots. If you have done it right, everything should fall in place. If not, recheck your arithmetic. Check transformations regardless, just to be sure.

- If after everything it still doesn't look right, move on and come back to it later.

bucket

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Re: Bucket's Questions
« Reply #333 on: November 05, 2008, 11:11:33 pm »
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Thats a good approach to it. The problem I have with endpoints is when I get something such as . I know it's probably very dumb but I don't know how to work these out when they are not the values I'm used to!!
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fredrick

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Re: Bucket's Questions
« Reply #334 on: November 05, 2008, 11:32:21 pm »
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Thats a good approach to it. The problem I have with endpoints is when I get something such as . I know it's probably very dumb but I don't know how to work these out when they are not the values I'm used to!!
is in the second quadrant and cos is negative in that quadrant. So just convert it to first quadrant and you get
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danieltennis

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Re: Bucket's Questions
« Reply #335 on: November 05, 2008, 11:35:35 pm »
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Thats a good approach to it. The problem I have with endpoints is when I get something such as . I know it's probably very dumb but I don't know how to work these out when they are not the values I'm used to!!
is in the second quadrant and cos is negative in that quadrant. So just convert it to first quadrant and you get

Another way is just to convert into degrees

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Re: Bucket's Questions
« Reply #336 on: November 05, 2008, 11:49:50 pm »
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Mmm, whenever I do a trial exam I always fuck up when i need to manually plot a trig graph. Does anybody have any tricks for doing these? I have the most difficulty determining endpoints and the y intercept whenever the graph is translated in any direction.

draw the most basic function, then follow the steps of transformations.

normally, you only need to draw one quarter of the graph, as the functions are all periodic and perfectly symmetrical.



as for the table of exact values, remember this:

for


and cos is the reverse of this order.
now just gotta remember how to use the unit circle and you have all the angles you need.
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bucket

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Re: Bucket's Questions
« Reply #337 on: November 06, 2008, 12:27:41 am »
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independent events vs mutually exclusive, whats the difference again and how do you find the probabilities of the intersection of these events.
« Last Edit: November 06, 2008, 01:19:37 pm by bucket »
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Collin Li

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Re: Bucket's Questions
« Reply #338 on: November 06, 2008, 12:33:26 am »
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If and are mutually exclusive, the probability of their intersection is zero.

Quote




If they are independent, then given one of them (conditional probability), the probability of the other is the same as the probability of the other alone. A consequence of this is that the probability of their intersection is the product of both the individual probabilities.

Quote


Since


« Last Edit: November 06, 2008, 12:37:12 am by coblin »

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Re: Bucket's Questions
« Reply #339 on: November 06, 2008, 12:35:18 am »
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Independent events (I'm assuming that's what you want because independent variables is a further/other sciences topic) are events where the probability of one event occuring does not affect the probability of another even occuring. The forumula is below

 

Mutually exclusive events are events where one event can not occur alongside another event i.e Thus the forumula is

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bucket

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Re: Bucket's Questions
« Reply #340 on: November 06, 2008, 12:38:16 am »
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thanks heaps guys
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bucket

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Re: Bucket's Questions
« Reply #341 on: November 06, 2008, 12:43:12 am »
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edit* I want to rephrase the question to be more general :P

How do I find when A and B are independent? :S
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fredrick

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Re: Bucket's Questions
« Reply #342 on: November 06, 2008, 12:43:57 am »
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add them?
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bucket

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Re: Bucket's Questions
« Reply #343 on: November 06, 2008, 12:44:38 am »
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So it's the same as the mutually exclusive events?
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Glockmeister

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Re: Bucket's Questions
« Reply #344 on: November 06, 2008, 12:50:24 am »
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yeah, you would need to have and to be able to work out
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