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January 11, 2026, 07:07:51 pm

Author Topic: Bucket's Questions  (Read 57516 times)  Share 

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fredrick

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Re: Bucket's Questions
« Reply #375 on: November 06, 2008, 05:23:08 pm »
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You've got two main conditions that need to be satisfied (the intersection of these two):

1)

2)

The second one is a bit more complicated:

Either (i) or (ii) are acceptable domains (i.e: the union of these domains constitute the 2nd condition)

i) if , then , hence:

ii) if , then , hence:

So, the maximal domain is the intersection of:

1) , and

2) the union of and

So you should get all real values excluding the region
or you can sketch the graph and pick the values above the x-axis
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Collin Li

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Re: Bucket's Questions
« Reply #376 on: November 06, 2008, 05:23:41 pm »
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Same thing. You're solving for the same numbers essentially. This is an analytical approach as opposed to a graphical approach.

rowshan

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Re: Bucket's Questions
« Reply #377 on: November 06, 2008, 08:58:57 pm »
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Coblin, howd you go from here

You've got two main conditions that need to be satisfied (the intersection of these two):

Either (i) or (ii) are acceptable domains (i.e: the union of these domains constitute the 2nd condition)

i) if , then , hence:

ii) if , then , hence:

So, the maximal domain is the intersection of:

2) the union of and

So you should get all real values excluding the region

to here?

Collin Li

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Re: Bucket's Questions
« Reply #378 on: November 06, 2008, 09:01:15 pm »
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Where to where?

That should be written as R\(-2,3]. I said it in words.

can be simplified by multiplying both sides by . However, it's not that simple for an inequality. If we multiply by a negative number, it changes the sign, which is why I have explored both cases.
« Last Edit: November 06, 2008, 09:03:07 pm by coblin »

cara.mel

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Re: Bucket's Questions
« Reply #379 on: November 06, 2008, 09:48:44 pm »
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Three threads.
You weren't attacking brendan and coblin, you were attacking my post alone. You didn't answer my question and used it just to mock me (possibly you don't have an answer to it, you seem incapable of explaining your contention)

Bucket: I can't fight with him elsewhere as he has blocked all methods of private correspondance. Quite useful when you borrow something and NEED TO GIVE IT BACK.

rowshan

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Re: Bucket's Questions
« Reply #380 on: November 06, 2008, 10:14:46 pm »
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yeah i read your answer properly coblin thanks a shit load =D
just a thought...how come we wernt taught this inequality stuff in earlier years?

lacoste

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Re: Bucket's Questions
« Reply #381 on: November 06, 2008, 10:19:15 pm »
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CHOCORATE ICED-CREAM LINKING TO AFRICAN CHILD ?~!~ NEW LEVEL ATTACK


you pisser!! made me laugh LAUGH OUT LOUD,,, reminds me of pokemon

bucket

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Re: Bucket's Questions
« Reply #382 on: November 06, 2008, 10:45:40 pm »
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Three threads.
You weren't attacking brendan and coblin, you were attacking my post alone. You didn't answer my question and used it just to mock me (possibly you don't have an answer to it, you seem incapable of explaining your contention)

Bucket: I can't fight with him elsewhere as he has blocked all methods of private correspondance. Quite useful when you borrow something and NEED TO GIVE IT BACK.
...get out of my question thread =_=
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vce01

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Re: Bucket's Questions
« Reply #383 on: November 06, 2008, 10:57:22 pm »
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Yup, I was just doing one then!

Let . Find the equation of the tangent to f(x) that passes through the origin.

can someone explain how to do this? thanks
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onlyfknhuman

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Re: Bucket's Questions
« Reply #384 on: November 06, 2008, 11:00:40 pm »
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what does it mean by passes through the origin? i thougth that meant passing through (0,0).
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Collin Li

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Re: Bucket's Questions
« Reply #385 on: November 06, 2008, 11:02:35 pm »
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Yup, I was just doing one then!

Let . Find the equation of the tangent to f(x) that passes through the origin.

can someone explain how to do this? thanks



We are looking for a tangent: , which passes through the origin, .

Therefore:



What else do we know? At the point when the tangent touches the curve, :

1)

2)

Substituting this into: at











Substituting this into equation 2:



Therefore, the tangent is

onlyfknhuman

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Re: Bucket's Questions
« Reply #386 on: November 06, 2008, 11:04:41 pm »
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ah fuck im such a retard lol

so pro coblin
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Collin Li

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Re: Bucket's Questions
« Reply #387 on: November 06, 2008, 11:06:47 pm »
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ah fuck im such a retard lol

so pro coblin

It's a sort of difficult question. Always think of these kind of questions as a quest to assemble the pieces of information you have to find what you want.

vce01

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Re: Bucket's Questions
« Reply #388 on: November 06, 2008, 11:07:59 pm »
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Yup, I was just doing one then!

Let . Find the equation of the tangent to f(x) that passes through the origin.

can someone explain how to do this? thanks



We are looking for a tangent: , which passes through the origin, .

Therefore:



What else do we know? At the point when the tangent touches the curve, :

1)

2)

Substituting this into: at











Substituting this into equation 2:



Therefore, the tangent is

awesome, thanks :)
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bucket

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Re: Bucket's Questions
« Reply #389 on: November 07, 2008, 12:00:02 am »
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This is from 2007 exam 1, i don't know why I have trouble with this =_=
Solve for
and

Let Find the smallest possible value of x of which g(x) is a maximum.
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