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October 22, 2025, 07:58:45 pm

Author Topic: Easy Chem help  (Read 10082 times)  Share 

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superflya

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Re: Easy Chem help
« Reply #15 on: January 15, 2010, 01:04:36 am »
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I think I wrote it wrong in the book it says Lead(IV)oxide (PbO2)...

Yeah do textbooks even make typo's....

A LOT OF TYPOS.
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andy456

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Re: Easy Chem help
« Reply #16 on: January 15, 2010, 01:05:51 am »
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Really...... why do we have to pay money for them if they have typo's......
It's very misleading as well......

Oh well.... what can you do?
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superflya

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Re: Easy Chem help
« Reply #17 on: January 15, 2010, 01:14:53 am »
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^^ live with it, no choice.
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andy456

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Re: Easy Chem help
« Reply #18 on: January 15, 2010, 11:32:33 am »
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I have another question.....

Magnesium reacts with hydrochloric acid according to the equation:
Mg(s) + 2HCl(aq) -> MgCl2(aq) + H2(g)
If 10.0g of magnesium reacts completely, calculate the mass of hydrogen that forms
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xD_aQt

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Re: Easy Chem help
« Reply #19 on: January 15, 2010, 11:42:38 am »
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I have another question.....

Magnesium reacts with hydrochloric acid according to the equation:
Mg(s) + 2HCl(aq) -> MgCl2(aq) + H2(g)
If 10.0g of magnesium reacts completely, calculate the mass of hydrogen that forms


n = = = 0.41152263374485596707818930041152
m = nM = 0.41152263374485596707818930041152 x 2 = 0.82304526748971193415637860082305 g
« Last Edit: January 15, 2010, 12:03:14 pm by xD_aQt »

andy456

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Re: Easy Chem help
« Reply #20 on: January 15, 2010, 11:45:41 am »
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Nah, sorry the answer in the back is 0.0824g......

I've done what you did, but i multiplied it by 2 because its H2
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the.watchman

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Re: Easy Chem help
« Reply #21 on: January 15, 2010, 11:46:20 am »
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I have another question.....

Magnesium reacts with hydrochloric acid according to the equation:
Mg(s) + 2HCl(aq) -> MgCl2(aq) + H2(g)
If 10.0g of magnesium reacts completely, calculate the mass of hydrogen that forms


n = = = 0.41152263374485596707818930041152
m = nM = 0.41152263374485596707818930041152 x 1 = 0.41152263374485596707818930041152 g

Is that right?

Shouldn't it be 2mol of hydrogen gas?
And please round off to the correct number of sigfigs :P
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andy456

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Re: Easy Chem help
« Reply #22 on: January 15, 2010, 11:48:22 am »
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^
Thats what i did but its still wrong
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xD_aQt

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Re: Easy Chem help
« Reply #23 on: January 15, 2010, 11:48:50 am »
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Nah, sorry the answer in the back is 0.0824g......

I've done what you did, but i multiplied it by 2 because its H2
does the back say 0.0824 g ? I thought the answer be 0.823 g

I have another question.....

Magnesium reacts with hydrochloric acid according to the equation:
Mg(s) + 2HCl(aq) -> MgCl2(aq) + H2(g)
If 10.0g of magnesium reacts completely, calculate the mass of hydrogen that forms


n = = = 0.41152263374485596707818930041152
m = nM = 0.41152263374485596707818930041152 x 1 = 0.41152263374485596707818930041152 g

Is that right?

Shouldn't it be 2mol of hydrogen gas?
And please round off to the correct number of sigfigs :P
I will round off .. my bad :P

andy456

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Re: Easy Chem help
« Reply #24 on: January 15, 2010, 11:50:09 am »
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Yeah it says 0.0824g but I also got 0.823g

Maybe its just another typo in the book
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xD_aQt

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Re: Easy Chem help
« Reply #25 on: January 15, 2010, 11:51:42 am »
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Yeah it says 0.0824g but I also got 0.823g

Maybe its just another typo in the book
Haha, could be! What book is this? Heinemann?

andy456

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Re: Easy Chem help
« Reply #26 on: January 15, 2010, 11:52:42 am »
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Yeah its heinemann.......  do they make typo's alot cause i found another one yesterday????
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xD_aQt

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Re: Easy Chem help
« Reply #27 on: January 15, 2010, 11:53:43 am »
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Yeah its heinemann.......  do they make typo's alot cause i found another one yesterday????
Yeah, they tend to make a few typo's! Just post up any questions that you think may have a typo in the answer section.

xD_aQt

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Re: Easy Chem help
« Reply #28 on: January 15, 2010, 11:54:33 am »
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by the way which question is this ? could you tell me the page?

andy456

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Re: Easy Chem help
« Reply #29 on: January 15, 2010, 11:57:19 am »
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Ummm this one was Chapter 2 Q14b. page.21
Btw Q14a worked fine.....

and the one from the other day was Chapter 2 Q10 page.18

Have you been studying for chemistry over the holidays?
VCE 2010: Eng 42 | Legal 49 | Chem 37 | MM 34 | Indo SL 33 |
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