Blakhitman's Questions!

[TrueTears]

So when f(x) = 0, x = 0

1 - 2k+5=0

k = 3

lim_{x -> -infty} f(x) = 5

so a = 5

f(x) = 0 we need to find x.

let u = e^(x)

u^2 - 6u + 5 = 0

solve for u and then x.

[TrueTears]

Actually jst4funz I wanna prove , can anyone show me how to finish this proof?



is defined from and assume

Thus for every there is a corresponding such that if then

But



But

[Blakhitman]

Thank you.

haha...wish I could return the favour by helping you with that...not gonna happen

[TrueTears]

np, kamil will do it for sure this is his kinda maths

[kamil9876]

I wouldn't bother with something like that. Better of proving the basic general laws and simply then applying them to special cases like these (although Kamil doesn't like to bother with these kinds of very special cases anyway).

[TrueTears]

I wouldn't bother with something like that. Better of proving the basic general laws and simply then applying them to special cases like these (although Kamil doesn't like to bother with these kinds of very special cases anyway).

well how would you finish off the proof, can you show me?

[Blakhitman]

O.k this was on our test, it's got to do with order of transformations...we never even talked about it in class :| I got it wrong, Wanna see what someone else gets!

The graph of y=|x| is transformed by the following sequence of transformations

• Translation of 5 units in the positive direction of the x-axis
• Translation of 6 units in the negative direction of the y-axis
• reflection in the x-axis

What's the rule of the image...

[naved_s9994]

y= - |x - 5|-6


Modulus is slightly different to other functions for transformations.

[Blakhitman]

haha oops I didn't give the choices ><

(a) y=6-|x-5|

(b) y=6+|x+5|

(c) y=-6+|x-5|

(d) y=6+|5-x|

(e) y=-6-|5-x|

[the.watchman]

y= - |x - 5|-6

Modulus is slightly different to other functions for transformations.

Actually, wouldn't it be ?
The reflection occurs after the translation...

[naved_s9994]

Im not sure.
Isnt it Dialation Reflection Translation..?

[superflya]

DRT or RDT, both work. 6 units in neg y so it should be -6?

[the.watchman]

Im not sure.
Isnt it Dialation Reflection Translation..?

But they specifically GIVE the sequence, so you have to follow what the question says? (I think)
Confirmation from anyone else?

[naved_s9994]

DRT or RDT, both work.

Ohh okay, wasnt sure of RDT.
I knew or DRT. Hence my answer..

[naved_s9994]

Im not sure.
Isnt it Dialation Reflection Translation..?

But they specifically GIVE the sequence, so you have to follow what the question says? (I think)
Confirmation from anyone else?

I have no idea about that..

Yea, please...Could anyone confirm?