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July 19, 2025, 08:27:46 am

Author Topic: Blakhitman's chem questions thread!  (Read 11404 times)  Share 

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Blakhitman

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Re: Blakhitman's chem questions thread!
« Reply #30 on: February 02, 2010, 08:07:55 pm »
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Thanks guys, I remember my methods teacher telling me how to remember now, something bout S.P.A.N.N.E.R, or was it S.P.A.N.N.A anyway I tried googling it but couldn't find anything on it and I can't remember what it means, anyone know this method?

Got it off teacher :D Spana Chops....Doesn't contain everything though.

SPANA

Compounds containing Sodium Potassium Ammonium Nitrate and Acetate ions are always soluble in water.

CHOPS

Compounds containing Carbonate Hydroxide Oxide Phosphate and Sulfide ions are generally water insoluble unless combined with SPANA ions.

Still, I think it can be quite useful.


Blakhitman

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Re: Blakhitman's chem questions thread!
« Reply #31 on: February 03, 2010, 07:16:12 pm »
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To separate these into half equations...would I write a half equation for both HgO into Hg, and HgO into O2?


Mao

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Re: Blakhitman's chem questions thread!
« Reply #32 on: February 03, 2010, 10:21:09 pm »
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To separate these into half equations...would I write a half equation for both HgO into Hg, and HgO into O2?



Yes
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Blakhitman

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Re: Blakhitman's chem questions thread!
« Reply #33 on: February 03, 2010, 10:24:53 pm »
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To separate these into half equations...would I write a half equation for both HgO into Hg, and HgO into O2?



Yes

Thanks a lot!

Why the hell didn't I discover this place in year 11?!

Mao

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Re: Blakhitman's chem questions thread!
« Reply #34 on: February 03, 2010, 11:20:16 pm »
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To separate these into half equations...would I write a half equation for both HgO into Hg, and HgO into O2?



Yes

Thanks a lot!

Why the hell didn't I discover this place in year 11?!

No worries. Here's some more for exercise.

Separate into two redox half equations:
a)
b)
« Last Edit: February 03, 2010, 11:22:21 pm by Mao »
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Blakhitman

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Re: Blakhitman's chem questions thread!
« Reply #35 on: February 06, 2010, 12:43:35 am »
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Thanks Mao, you're a legend!

Ok need help with this... how would I go about working it? Thanks in advance to anyone that can help!

An organic compound underwent combustion. it was known to contain only Carbon, Hydrogen and Oxygen. It was analysed by burning a 1.00g sample in air. If 1.91g of CO2 and 1.17g of H2O was produced, what was the empirical formula of the compound.

fady_22

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Re: Blakhitman's chem questions thread!
« Reply #36 on: February 06, 2010, 10:10:24 am »
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First calculate the number of moles of carbon dioxide and water:




From this, you can calculate the number of mole of hydrogen and carbon in the compound:
and

Now you can calculate the masses of both carbon and hydrogen in the sample, and subtract the masses from the mass of the organic compound, giving 1-0.65=0.35 g of Oxygen.

Now, find the number of mole of oxygen:


Now that you have the number of mole of carbon, hydrogen and oxygen, you can find the ratio in which they are found in the compound:
n(C):n(H):n(O)
2:6:1
Therefore, the empirical formula is:
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Blakhitman

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Re: Blakhitman's chem questions thread!
« Reply #37 on: February 06, 2010, 10:39:59 am »
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Thank you so much!

And is your name really Fady?

fady_22

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Re: Blakhitman's chem questions thread!
« Reply #38 on: February 06, 2010, 10:41:02 am »
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Thank you so much!

And is your name really Fady?

Just saw your email... your name is Fady too lol.
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Blakhitman

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Re: Blakhitman's chem questions thread!
« Reply #39 on: February 06, 2010, 10:42:32 am »
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Ok, was just wondering as my name is also Fady ><

Pretty cool :D almost same subjects too.

Blakhitman

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Re: Blakhitman's chem questions thread!
« Reply #40 on: February 06, 2010, 10:43:05 am »
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Thank you so much!

And is your name really Fady?

Just saw your email... your name is Fady too lol.

haha yep

Blakhitman

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Re: Blakhitman's chem questions thread!
« Reply #41 on: February 07, 2010, 05:13:19 pm »
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First calculate the number of moles of carbon dioxide and water:




From this, you can calculate the number of mole of hydrogen and carbon in the compound:
and

Now you can calculate the masses of both carbon and hydrogen in the sample, and subtract the masses from the mass of the organic compound, giving 1-0.65=0.35 g of Oxygen.

Now, find the number of mole of oxygen:


Now that you have the number of mole of carbon, hydrogen and oxygen, you can find the ratio in which they are found in the compound:
n(C):n(H):n(O)
2:6:1
Therefore, the empirical formula is:


O.k I forgot to give you some info, would it matter if I gave you the equation of the process? or would it just make it easier?

Yes that includes the molecular formula  :-[

C2H2O + 2O2 --> 2CO2 + H2O

EDIT: wait can't I just use the 1.00 g to work out the mol of Carbon, Hydrogen and Oxygen in the compound given the formula of it? then do ratios? Man chem is confusing.
« Last Edit: February 07, 2010, 05:16:55 pm by Blakhitman »

Blakhitman

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Re: Blakhitman's chem questions thread!
« Reply #42 on: February 21, 2010, 02:07:46 pm »
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Why is each of the elements, Nitrogen, Phosphorus, Sulfur and Iron included in Lawn food?

Edmund

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Re: Blakhitman's chem questions thread!
« Reply #43 on: February 21, 2010, 02:29:27 pm »
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the.watchman

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Re: Blakhitman's chem questions thread!
« Reply #44 on: February 21, 2010, 02:31:03 pm »
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Remember, remember the 5th of November

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